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Mademuasel [1]
4 years ago
12

Solving 8 problems per minute, Fast Finn can finish his test in time. He was however, working faster, solving 10 problems per mi

nutes. That is why he finished 6 minutes early. How many problems were on the test.Solving 8 problems per minute, Fast Finn can finish his test in time. He was however, working faster, solving 10 problems per minutes. That is why he finished 6 minutes early. How many problems were on the test?
Mathematics
1 answer:
mrs_skeptik [129]4 years ago
4 0

Answer:

Number of problems = 240

Step-by-step explanation:

Let x be the number of questions and t be the time.

Given:

Average rate = 8 problems per minute

Fast Finn rate = 10 problems per minute

Fast Finn taken time = t - 6

We need to find the number of problems on the test paper.

Solution:

Average rate to solve test paper.

Average\ rate =\frac{Number\ of\ questions}{time}  

8 =\frac{x}{t}

t =\frac{x}{8} --------------(1)

Fast Finn rate to solve the test paper.

Average\ rate =\frac{Number\ of\ questions}{time}  

10 =\frac{x}{t-6}

Using cross multiplication rule.

x=10(t-6)

x=10t-60

substitute t =\frac{x}{8}  from equation 1.

x=10(\frac{x}{8}) -60

Rearrange the equation as:

x - \frac{5}{4}x = -60

\frac{4x-5x}{4}=-60

-\frac{x}{4} =  -60

Using cross multiplication rule.

x = 60\times 4

x = 240 problems.

Therefore, 240 problems were on the test.

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Answer:

  5

Step-by-step explanation:

<u>Given</u>:

  A = (a, 14-a)

  P = (3a, a^2 +13a -11)

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  a > 0

<u>Find</u>:

  a

<u>Solution</u>:

The slope of AP is ...

  m = (Py -Ay)/(Px -Ax)

  7 = (a^2 +13a -11 -(14 -a))/(3a -a)

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The value of 'a' is 5.

_____

<em>Check</em>

The point A is (a, 14-a) = (5, 9).

The point P is (3a, a^2 +13a -11) = (15, 79)

The slope of AP is (79 -9)/(15 -5) = 70/10 = 7.

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