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uranmaximum [27]
3 years ago
10

There is a line that includes the point (-1, -1) and has a slope of 0. What is its equation in slope-intercept form?

Mathematics
1 answer:
tresset_1 [31]3 years ago
6 0

Answer:

y=-1

Step-by-step explanation:

The slope intercept form of a line is

y = mx +b where m is the slope and b is the y intercept

We know the slope is zero

y = 0x+ b

Substituting the values for x=-1 and y=-1 from the point we are given

-1 =0 +b

b=-1

Putting this into the original equation

y = 0x+-1

y=-1

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Answer:

The slope and y-intercept values indicate characteristics of the relationship between the two variables x and y. The slope indicates the rate of change in y per unit change in x.

Step-by-step explanation:

6 0
3 years ago
For what values of q are the two vectors A = i + j + kq each other and B-iq-23 + 2kg perpendicular to
Sloan [31]

Answer:

The value of q are 0.781,-1.281.

Step-by-step explanation:

Given : Two vectors A=i+j+kq and B=iq-2j+2kq are perpendicular to each other.

To find : The value of q ?

Solution :

When two vectors are perpendicular to each other then their dot product is zero.

i.e. \vec{A}\cdot \vec{B}=0

Two vectors A=i+j+kq and B=iq-2j+2kq

(i+j+kq)\cdot (iq-2j+2kq)=0

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q-2+2q^2=0

2q^2+q-2=0

2q^2+q-2=0

Using quadratic formula,

q=\frac{-1\pm\sqrt{1^2-4(2)(-2)}}{2(2)}

q=\frac{-1\pm\sqrt{17}}{4}

q=\frac{-1+\sqrt{17}}{4},\frac{-1-\sqrt{17}}{4}

q=0.781,-1.281

Therefore, The value of q are 0.781,-1.281.

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Read 2 more answers
State the equation of the line in y = mx + b form.
gtnhenbr [62]
Your slope is wrong! Your slope is going to be 3/2, or C for the first problem. Your y intercept is wrong! Your Y- intercept is actually (0, -1.3) or B for the second problem.
Your equation is going to be
y= 3/2x-1.3
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