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uranmaximum [27]
3 years ago
10

There is a line that includes the point (-1, -1) and has a slope of 0. What is its equation in slope-intercept form?

Mathematics
1 answer:
tresset_1 [31]3 years ago
6 0

Answer:

y=-1

Step-by-step explanation:

The slope intercept form of a line is

y = mx +b where m is the slope and b is the y intercept

We know the slope is zero

y = 0x+ b

Substituting the values for x=-1 and y=-1 from the point we are given

-1 =0 +b

b=-1

Putting this into the original equation

y = 0x+-1

y=-1

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After shopping, it took Manuel 87 seconds to push a shopping cart directly to his car. In one-
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The carts velocity= 2m/s

Step-by-step explanation:

It took Manuel 87 seconds to push a shopping cart directly to his car.

One third of 87 = 87/3 = 29

In 29 seconds the carts moved 58 meter's.

The carts velocity = distance/time

The carts velocity = 58/29

The carts velocity= 2m/s

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Find the sum of the first 15 terms of the arithmetic of the sequence where the 1st term is 3200 and the common difference is 150
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4 years ago
Alejandra Plans to sew fringe on a scarf. The scarf is shaped like a rectangle. The length of the scarf is 48 inches. The width
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3 years ago
ASK YOUR TEACHER An article reported that for a sample of 42 kitchens with gas cooking appliances monitored during a one-week pe
xxMikexx [17]

Answer:

654.16-2.02\frac{165.23}{\sqrt{42}}=602.66    

654.16+2.02\frac{165.23}{\sqrt{42}}=705.66    

So on this case the 95% confidence interval would be given by (602.66;705.66)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=654.16 represent the sample mean

\mu population mean (variable of interest)

s=165.23 represent the sample standard deviation

n=42 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=42-1=41

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,41)".And we see that t_{\alpha/2}=2.02

Now we have everything in order to replace into formula (1):

654.16-2.02\frac{165.23}{\sqrt{42}}=602.66    

654.16+2.02\frac{165.23}{\sqrt{42}}=705.66    

So on this case the 95% confidence interval would be given by (602.66;705.66)    

7 0
4 years ago
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