We have that
csc ∅=13/12
sec ∅=-13/5
cot ∅=-5/12
we know that
csc ∅=1/sin ∅
sin ∅=1/ csc ∅------> sin ∅=12/13
sec ∅=-13/5
sec ∅=1/cos ∅
cos ∅=1/sec ∅------> cos ∅=-5/13
sin ∅ is positive and cos ∅ is negative
so
∅ belong to the II quadrant
therefore
<span>the coordinates of point (x,y) on the terminal ray of angle theta are
</span>x=-5
y=12
the answer ispoint (-5,12)
see the attached figure
Answer:
The circle has a center at (5.-1) and radius of 2 units.
Step-by-step explanation:
Answer:
54 cups of flour
Step-by-step explanation:
Answer:
12
Step-by-step explanation:
This is a joint variation problem:
z varies directly as x and y
Interpreting this;
z ∝ xy
Therefore;
z = kxy
z = 6, x = 2, y = 6
Now find k,
6 = 2 x 6 x k
6 = 12k
k =
To find the value of z;
x = 3, y = 8
z =
x 3 x 8 = 12
2/3 n = -12 Write equation
(3/2) 2/3n = -12/1 (3/2) Isolate n
n = -36/2 Simplify
n = -18 Answer