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Lyrx [107]
3 years ago
14

Problem is Sin38-cos52

Mathematics
1 answer:
Paha777 [63]3 years ago
3 0
Notice that 38 and 52 make a total of 90
sinA=cos(90-A)
sin38=cos52, therefore the answer is zero
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Solve the simultaneous equation y-2x+1=0 and 4x^2+3y^2-2xy=7
Lapatulllka [165]

The first equation is y-2x+1=0

y=2x-1 (Equation 1)

The second equation is 4x^{2}+3y^{2}-2xy=7 (Equation 2)

Putting the value of x from equation 1 in equation 2.

we get,

4x^{2}+3(2x-1)^{2}-2x(2x-1)=7

4x^{2}+3(4x^{2}+1-4x)-4x^{2}+2x=7

by simplifying the given equation,

12x^{2}-10x-4=0

6x^{2}-5x-2=0

Using discriminant formula,

D=b^{2}-4ac

D=25-4 \times 6 \times -2 = 73

Now the formula for solution 'x' of quadratic equation is given by:

x=\frac{-b+\sqrt{D}}{2a}  and  x=\frac{-b-\sqrt{D}}{2a}

x=\frac{5+\sqrt{73}}{12}  and x=\frac{5-\sqrt{73}}{12}

Hence, these are the required solutions.

8 0
3 years ago
1 ≤ n, k ≤ 10 ^ 5 1 ≤ x ≤ 10 ^ 5<br> Alguém me ajuda?
enot [183]

Answer:

ask your teacher for help

Step-by-step explanation:

8 0
3 years ago
Solve for x in the diagram below
ella [17]

Answer:

20

Step-by-step explanation:

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8 0
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A bowling leagues mean score is 197 with a standard deviation of 12. The scores are normally distributed. What is the probabilit
Bond [772]

Answer:

0.281 = 28.1% probability a given player averaged less than 190.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

A bowling leagues mean score is 197 with a standard deviation of 12.

This means that \mu = 197, \sigma = 12

What is the probability a given player averaged less than 190?

This is the p-value of Z when X = 190.

Z = \frac{X - \mu}{\sigma}

Z = \frac{190 - 197}{12}

Z = -0.58

Z = -0.58 has a p-value of 0.281.

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8 0
3 years ago
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Serhud [2]

The given statement is:

41 fewer than the quantity t times 307 is equal to n.

The equation is given by:

307t-41=n

3 0
1 year ago
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