The solutions to the given system of equations are x = 4 and y = -9
<h3>Simultaneous linear equations</h3>
From the question, we are to determine the solutions to the given system of equations
The given system of equations are
-8x-4y=4 --------- (1)
-5x-y=-11 --------- (2)
Multiply equation (2) by 4
4 ×[-5x-y=-11 ]
-20x -4y = -44 -------- (3)
Now, subtract equation (3) from equation (1)
-8x -4y = 4 --------- (1)
-(-20x -4y = -44) -------- (3)
12x = 48
x = 48/12
x = 4
Substitute the value of x into equation (2)
-5x -y = -11
-5(4) -y = -11
-20 -y = -11
-y = -11 + 20
-y = 9
∴ y = -9
Hence, the solutions to the given system of equations are x = 4 and y = -9
Learn more on Simultaneous linear equations here: brainly.com/question/26310043
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I don’t have a calculator right now but a triangle always adds up to 180 degrees so yeah
X would equal 9. Subtract 18 from both sides then divide by two to get 9 as X
Answer:
Step-by-step explanation:
Let x represent the total number of stdents that has all grades in the school.
There are three grades in the school. One grade has 1/3 of the students, this means that number of students that belongs tho this grade is 1/3 × x = x/3
One grade has 1/4 of the students, this means that number of students that belongs to this grade is 1/4 × x = x/4
Total number of students in both grades would be x/3 +/x/4 = 7x/12
The number of students in the remaining grade would be
x - 7x/12 = 5x/12
fraction of students in the remaining grade would be
(5x/12)/x = 5/12
Part A you would use 200-L ( since you have 400 feet total 200 feet would equal length plus width)
Part B 200 - 80 = 120
Part C 200-90 = 110
area = 90 x 110 = 9900 square feet
