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3 years ago

5

Which set of parametric equations over the interval 0 ≤ t ≤ 1 defines a line segment with initial point (–5, 3) and terminal poi

nt (1, –6)?

1 answer:

Strike441 [17]3 years ago

6 0

Answer:

x(t) = –5 + 6t; y(t) = 3 – 9t

Step-by-step explanation:

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What is the slope of the line that passes through the points (-9, -7) and<br> (-11, 6)

anzhelika [568]

Answer:

-13/2

Step-by-step explanation:

-13/2 is the answer

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2 years ago

Combine like terms.<br><br> 8y2 + 8(7y2 − 9) =

djverab [1.8K]

Answer:

8 • (8y2 - 9)

Step-by-step explanation:

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3 years ago

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The graph shows the daily sales goal of

posledela

Answer:

25 cups of tea

Step-by-step explanation:

On the x-axis, we have the number of cups of coffee plotted against the number of cups of tea which are plotted on the y-axis to represent the daily sales goals.

From the graph, when 20 cups of coffee are sold (x = 20), a corresponding sales of 25 cups of tea (y = 25) would be sold as well to meet the sales goal.

Therefore, when employees sell 20 cups of coffee, 25 cups of tea must be sold to meet their goal.

6 0

3 years ago

I NEED HELP ASAP PLEASE NO LINKS!!!

Ludmilka [50]

Answer:

1/8

Step-by-step explanation:

I looked it up lol

8 0

3 years ago

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I need help, I don’t need an explanation, just the answer

meriva

Answer:

$x = 48 \: \: \: \: \: \: y = 16$

Step-by-step explanation:

$y = - x + 4y$

$y + x = 4y$

$y + x - 4y = 0$

$- 3y + x = 0$

$- x + 4y = 16$

$- 3y + x = 0$

$- 3y = - x$

$y = - \frac{1}{3} ( - 1)x$

$y = \frac{1}{3} x$

$4 \times ( \frac{1}{3} )x - x = 16$

$\frac{1}{3}x = 16$

$x = 48$

$y = \frac{1}{3} \times 48$

$y = 16$

Hope this is correct and helpful

HAVE A GOOD DAY!

5 0

3 years ago

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