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svp [43]
3 years ago
5

I need help please fast

Mathematics
1 answer:
JulsSmile [24]3 years ago
8 0
What do unwed help on
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If f(x) = -5x - 1, find the function value f(1).<br><br> f(1) =
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Answer: f(1) = -6

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3 years ago
During a road trip Tony , Tony drove one third the distance that Lana drove. Mark drives 15 more than Lana drove .The total dist
ale4655 [162]

Answer:

The distance drive by Lana = 201 miles

The distance drive by Mark = 216 miles

The distance drive by Tony = 67 miles  

Step-by-step explanation:

Given as :

The total distance cover by Lana , Tony , Mark = 484   miles

Let The distance drove by Lana = L   miles

The distance drove by Tony = T

The distance cover by Mark = M

So ,  L + T + M = 484 miles

Now, The distance of Tony = \frac{1}{3} of Lana distance

Or,   T = \frac{1}{3} × L

And The distance of Mark = 15 + The distance of Lana

Or,   M = 15 + L

Now.

   L + \frac{1}{3} × L + 15 + L = 484

Or, 2 L + \frac{L}{3} = 484 - 15

Or,  2 L + \frac{L}{3} = 469

Or,  \frac{7 L}{3} = 469

Or,  7 L = 469 × 3

∴     L =  \frac{1407}{7}

I.e   L = 201

The distance drive by Lana = 201 miles

The distance drive by Mark = 15 + L =15 + 201 = 216 miles

The distance drive by Tony =  \frac{1}{3} × 201 = 67 miles

Hence The distance drive by each person is

The distance drive by Lana = 201 miles

The distance drive by Mark = 216 miles

The distance drive by Tony = 67 miles    Answer

8 0
3 years ago
Factor Completely 14bx^2-7x^3-4b+2x
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=14bx2−7x3−4b+2x

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16/21 divided by 4/9 is equivalent to 16/21 x 9/4 = 144/84 which reduces to 12/7. So 12/7 is your answer.
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What is the value of the expression
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(-\dfrac{3^2}{3^3} )^2 = (-\dfrac{1}{3} )^2 = \dfrac{1}{9}


OR (in more details):


(-\dfrac{3^2}{3^3} )^2 = (-3^{2-3})^2 = (-3^{-1})^2 = (-\dfrac{1}{3} )^2 = \dfrac{1}{9}


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4 years ago
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