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3 years ago

Slope= 5 passing through (-4,6)

Mathematics

1 answer:

olga2289 [7]3 years ago

4 0

Answer:

y = 5x +26

Step-by-step explanation:

y - y1 = m(x - x1)

y - 6 = 5(x - -4)

y - 6 = 5(x + 4)

y - 6 = 5x +20

y = 5x + 26

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Explanation please will give brainliest.

Sonja [21]

Answer:

$AC = 28$

Step-by-step explanation:

Given

$AB = 16$

$BC = 12$

Required

Determine AC

Since A, B and C are collinear, then:

$AC = AB + BC$

So, we have:

$AC = 16 + 12$

$AC = 28$

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3 years ago

Help? Which angles are adjacent angles?

leva [86]

Answer:

They are two angles that have a common vertex and a common side.

Step-by-step explanation:

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3 years ago

Read 2 more answers

Find the exact value of each trigonometric function for the given angle θ.

Kay [80]

Answer:

$\sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=\dfrac{2}{\sqrt{3}}.$

Step-by-step explanation:

The given angle is 240 degrees.

We need to find the exact value of each trigonometric function for the given angle θ.

Since $\theta=240$ , it means θ lies in 3rd quadrant. In 3d quadrant only tan and cot are positive.

$\sin (240^\circ)=\sin (180^\circ+60^\circ)=-\sin (60^\circ)=-\dfrac{\sqrt{3}}{2}$

$\cos (240^\circ)=\cos (180^\circ+60^\circ)=-\cos (60^\circ)=-\dfrac{1}{2}$

$\tan (240^\circ)=\tan (180^\circ+60^\circ)=\tan (60^\circ)=\sqrt{3}$

$\cot (240^\circ)=\cot (180^\circ+60^\circ)=\cot (60^\circ)=\dfrac{1}{\sqrt{3}}$

$\sec (240^\circ)=\sec (180^\circ+60^\circ)=-\sec (60^\circ)=-2$

$\csc (240^\circ)=\csc (180^\circ+60^\circ)=-\csc (60^\circ)=-\dfrac{2}{\sqrt{3}}$

Therefore, $\sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=-\dfrac{2}{\sqrt{3}}.$

8 0

3 years ago

What is the inverse and restricted domain of the equation 8x^2-3

kari74 [83]

Answer: $\bold{y=\pm \dfrac{\sqrt{2(x+3)}}{4},\qquad x\neq -3}$

Step-by-step explanation:

y = 8x² - 3 (Restriction: none - x is All Real Numbers)

The inverse is when you swap the x's and y's and then solve for y

x = 8y² - 3 swapped the x and y

x + 3 = 8y² added 3 to both sides

$\dfrac{x+3}{8}=y^2$ divided both sides by 8

$\sqrt{\dfrac{x+3}{8}}=\sqrt{y^2}$ square rooted both sides

$\pm \sqrt{\dfrac{x+3}{8}}=y$ simplified

$\pm \sqrt{\dfrac{x+3}{8}\bigg(\dfrac{2}{2}\bigg)}=y$ rationalized the denominator

$\pm \sqrt{\dfrac{2(x+3)}{16}}=y$ simplified

$\pm \dfrac{\sqrt{2(x+3)}}{4}=y$ simplified

Restriction:

The radical (inside the square root sign) cannot be negative

→ 2(x + 3) ≥ 0

x + 3 ≥ 0 divided both sides by 2

x ≥ -3 subtracted 3 from both sides

4 0

3 years ago

Helppp ill mark u as brainlist

VMariaS [17]

Answer:

Part A: To find how much weight this insect can lift, you can multiply the equation's answer by the insect's weight. You would multiply the insect's weight by 1,182.

Part B: You need to multiply your weight, in pounds, by 1,182.

7 0

3 years ago