Answer:
Step-by-step explanation:
1) This Stem and Leaf plot works like a Histogram. Completing the question, check below the Stem plot. Look the data out of the Stem plot and within (in the graph below)
32, 34
, 38
, 39
, 39
, 40
, 43
, 45
, 46
, 49
, 53
, 54
, 57
, 58
, 59
, 59
, 63
, 68
2) Notice how the first digit is on the Stem column (check below)
3) To find the first and Third Quartiles
Let's use the formulas to find the position, then the value. As it follows:
The Earth's circumference is 24,901 miles.
Assuming an apple is 3 inches wide:
3.7 trillion apples is 3/12/5280*3000000000000=142045454.545 miles.
That is 142045454.545/24901=5704.408 times around the Earth.
Answer:
1.) Triangle ABC is congruent to Triangle CDA because of the SAS theorem
2.) Triangle JHG is congruent to Triangle LKH because of the SSS theorem
Step-by-step explanation:
Alright. Let's start with the 1st figure. How do we prove that triangles ABC and CDA (they are named properly) are congruent? First, we can see that segments BC and AD have congruent markings, so that can help us. We also see a parallel marking for those segments as well, meaning that the diagonal AC is also a transversal for those parallel segments. That means we can say that angle CAD is congruent to angle ACB because of the alternate interior angles theorem. Then, the 2 triangles also share the side AC (reflexive property).
So, we have 2 congruent sides and 1 congruent angle for each triangle. And in the way they are listed, this makes the triangles congruent by the SAS theorem since the angle is adjacent to the 2 sides that are congruent.
The second figure is way easier. As you can clearly see by the congruent markings on the diagram, all the sides on one triangle are congruent to the other. So, since there are 3 sides congruent, we can say the triangles JHG and LKH are congruent by the SSS theorem.
Answer:
you didn't feature any graphs for me to choose from
Answer:
(√74, 54.46°)
Step-by-step explanation:
The rectangular coordinate point is given as; (5, 7)
Now, converting rectangular coordinates to polar coordinates is done by;
(r, θ)
Where, r is the magnitude while θ is the angle
r = √(5² + 7²)
r = √74
tan θ = (7/5)
θ = tan^(-1) 1.4
θ = 54.46°
Thus,polar coordinate is; (√74, 54.46°)
