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OLga [1]
3 years ago
9

The shaded region in the figure shows recommended weight and height combinations. Determine the recommended weight range for a p

erson who is 78 inches tall.
Mathematics
1 answer:
vitfil [10]3 years ago
8 0
5h - w = 170
for h = 77
w = 5h - 170
w = 5*77 - 170
w = 385 - 170
<span>w = 215

Shoutout to @himanshuchaturvedi 

Your answer is : w = 215 

Have an amazing day and stay hopeful!

</span>
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Justin walked 3 miles north and 6 miles west. starting from the same point, tina walked 2 miles south and 4 miles east. how far
Darya [45]
Basically, Justin and Tina's paths form two right-angled triangles whose hypotenuses(?) form a straight line between their end points. Therefore we need to find the two distances from the starting point and add them.
Justin walked 3 miles north and 6 miles west so his distance from the start is the square root of 9+36 or 45. This can be simplified to 3√5. 
Tina walked 2 miles south and 4 miles east so her distance from the starting point is the square root of 4 + 16 or 20. This can be written as 2√5.
If we add these two distances together we get 5√5. Hence, Justin and Tina are 5√5 miles away from each other.
6 0
3 years ago
If a+b=9 and ab=18,find the value of a and b.
Blizzard [7]

Answer:

Given:

a + b = 9

=> a = 9 - b

Given:

a x b = 18

=> (9 - b) x b = 18

=> 9b - b^2 = 18

=> b^2 - 9b + 18 = 0

=> (b - 3)(b - 6) = 0

=> b = 3 => a = 6

=> b = 6 => a = 3

Hope this helps

:)

3 0
3 years ago
Find the area of the sector in<br> terms of pi.<br> 120°<br> 24<br> Area = [?] π<br> Enter
Nady [450]
Sector area= theta/360 x πr^2

Radius= 24/2= 12

Sector area= 120/360 x π(12)^2

Final answer :

Sector area = 48π
3 0
2 years ago
I need help answering an equation in standard form y-4 =0
MissTica
I think that equation might have no solution
6 0
3 years ago
Read 2 more answers
I have to transfer this graph into a vertex form equation, but I'm not sure how to.​
tino4ka555 [31]

Answer: y = -2/3(x-3)^2 + 0 or y = -2/3(x-3)^2

Step-by-step explanation:

vertex form is y=a(x-h)^2 + k

here we can see the vertex is (3,0) which is (x,y). Or (h,k) in this case.

so to plug that into vertex form, we now have y=a(x-3)^2 + 0. or just y=a(x-3)^2.

now we need to find "a" which is the leading coefficient. to do that we can plug in the (6,-6) for the x and y parts of the above equation. so we'd have

-6=a(6-3)^2. which goes to -6=a(2)^2 which is -6=4a. divide each side by 4 to get a = -2/3. plug this in for a

the final equation would be y = -2/3(x-3)^2 + 0 or y = -2/3(x-3)^2

8 0
2 years ago
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