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4 years ago

Susie said the relation above is also a function. Explain why Susie is correct or incorrect

Mathematics

1 answer:

astra-53 [7]4 years ago

5 0

Correct because X doesn't repeat its self

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Grace sold 84 of the 140 cokies she baked what pecent did she sell

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She sold 60% of her cookies.

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What are the coordinates of one of the vertices of a rectangle when two sides are given by the lines x - 3y = -8 and 3x + y = 6?

Aleonysh [2.5K]

Answer:

(1, 3)

Step-by-step explanation:

x - 3y = -8

3x + y = 6

Isolate a variable in one of the equations:

y = 6 - 3x

Substitute the value of y into the other equation:

x - 3(6 - 3x) = -8

Use distributive property:

x - 18 + 9x = -8

Combine like terms:

10x - 18 = -8

Isolate the variable:

10x = 10

x = 1

Substitute the value of x into any equation:

3(1) + y = 6

3 + y = 6

Isolate the variable:

y = 3

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3 years ago

A student S is suspected of cheating on exam, due to evidence E of cheating being present. Suppose that in the case of a cheatin

Kay [80]

Answer:

Step-by-step explanation:

Suppose we think of an alphabet X to be the Event of the evidence.

Also, if Y be the Event of cheating; &

Y' be the Event of not involved in cheating

From the given information:

$P(\dfrac{X}{Y}) = 60\% = 0.6$

$P(\dfrac{X}{Y'}) = 0.01\% = 0.0001$

$P(Y) = 0.01$

Thus, $P(Y') \ will\ be = 1 - P(Y)$

P(Y') = 1 - 0.01

P(Y') = 0.99

The probability of cheating & the evidence is present is = P(YX)

$P(YX) = P(\dfrac{X}{Y}) \ P(Y)$

$P(YX) =0.6 \times 0.01$

$P(YX) =0.006$

The probabilities of not involved in cheating & the evidence are present is:

$P(Y'X) = P(Y') \times P(\dfrac{X}{Y'})$

$P(Y'X) = 0.99 \times 0.0001 \\ \\ P(Y'X) = 0.000099$

(b)

The required probability that the evidence is present is:

P(YX or Y'X) = 0.006 + 0.000099

P(YX or Y'X) = 0.006099

(c)

The required probability that (S) cheat provided the evidence being present is:

Using Bayes Theorem

$P(\dfrac{Y}{X}) = \dfrac{P(YX)}{P(Y)}$

$P(\dfrac{Y}{X}) = \dfrac{P(0.006)}{P(0.006099)}$

$P(\dfrac{Y}{X}) = 0.9838$

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3 years ago

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Answer:

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3 years ago

In a secondary school class, 23 pupils study Economics, 6 pupils study both Government and Economics. 48 pupils study either Gov

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Step-by-step explanation:

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