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2 years ago

Mathematics I need help

Mathematics

1 answer:

Mkey [24]2 years ago

8 0

Answer:

The answer is b

Step-by-step explanation:

0.63-0.2=0.43

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If 2x = 5, 3y = 4, and 4z = 3, what is the value of 24xyz ?

NISA [10]

2x=5 so 5÷2 = x (2.5)
3y = 4 so 4÷3 = y (1.3 recurring)
4z = 3 so 3÷4 = z (0.75)

implement: 24x2.5x1.3•x0.75

hope i answered right

3 0

3 years ago

Factorise each of the following algebraic expressions completely,

LekaFEV [45]

Answer:

see explanation

Step-by-step explanation:

(a)

Given

2k - 6k² + 4k³ ← factor out 2k from each term

= 2k(1 - 3k + 2k²)

To factor the quadratic

Consider the factors of the product of the constant term ( 1) and the coefficient of the k² term (+ 2) which sum to give the coefficient of the k- term (- 3)

The factors are - 1 and - 2

Use these factors to split the k- term

1 - k - 2k + 2k² ( factor the first/second and third/fourth terms )

1(1 - k) - 2k(1 - k) ← factor out (1 - k) from each term

= (1 - k)(1 - 2k)

1 - 3k + 2k² = (1 - k)(1 - 2k) and

2k - 6k² + 4k³ = 2k(1 - k)(1 - 2k)

(b)

Given

2ax - 4ay + 3bx - 6by ( factor the first/second and third/fourth terms )

= 2a(x - 2y) + 3b(x - 2y) ← factor out (x - 2y) from each term

= (x - 2y)(2a + 3b)

8 0

3 years ago

One urn contains one blue ball (labeled B1) and three red balls (labeled R1, R2, and R3). A second urn contains two red balls (R

marusya05 [52]

Answer:

(a) See attachment for tree diagram

(b) 24 possible outcomes

Step-by-step explanation:

Given

$Urn\ 1 = \{B_1, R_1, R_2, R_3\}$

$Urn\ 2 = \{R_4, R_5, B_2, B_3\}$

Solving (a): A possibility tree

If urn 1 is selected, the following selection exists:

$B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]$

If urn 2 is selected, the following selection exists:

$B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]$

See attachment for possibility tree

Solving (b): The total number of outcome

For urn 1

There are 4 balls in urn 1

$n = \{B_1,R_1,R_2,R_3\}$

Each of the balls has 3 subsets. i.e.

$B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]$

So, the selection is:

$Urn\ 1 = 4 * 3$

$Urn\ 1 = 12$

For urn 2

There are 4 balls in urn 2

$n = \{B_2,B_3,R_4,R_5\}$

Each of the balls has 3 subsets. i.e.

$B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]$

So, the selection is:

$Urn\ 2 = 4 * 3$

$Urn\ 2 = 12$

Total number of outcomes is:

$Total = Urn\ 1 + Urn\ 2$

$Total = 12 + 12$

$Total = 24$

5 0

2 years ago

2. Solve the equation. (50 Points) * = + 9 = 30 Enter your math answer

barxatty [35]

Answer:

x= 42

Step-by-step explanation:

x/2+9=30

x+18=60

x=60-18

x= 42

5 0

3 years ago

Read 2 more answers

An engineer is designing a fountain that shoots out drops of water. The nozzle from which the water is launched is 3 meters abov

Hoochie [10]

Answer:

After 3 seconds

Step-by-step explanation:

Given

$h(t) = -5t^2 + 14t + 3$

Required

Time the drop will hit the ground

When the drop hits the ground,

$h(t) = 0$

So, we have:

$0 = -5t^2 + 14t + 3$

Rewrite as:

$5t^2 - 14t - 3 = 0$

Expand

$5t^2 + t - 15t - 3 = 0$

Factorize

$t(5t + 1) -3(5t + 1) = 0$

Factor out 5t + 1

$(t -3)(5t + 1) = 0$

Split

$t -3 = 0$ or $5t + 1 = 0$

Solve for t

$t = 3$ or $5t = -1$

Time cannot be negative.

So:

$t = 3$

5 0

3 years ago