Question

line p contains point (-3, 0) and is perpendicular to line q. The equation for line q is y=2x + 4 find the slope of line p. Then write an equation for line p in point-slope form y-y=m(x-x).​

Answer 1

Answer:

y = 2x + 6

Step-by-step explanation:

The equation for line p can be written since parallel lines have the same slope. This means the slope of line q which is 2 is the same for line p. Substitute m = 2 and the point (-3,0) into the point slope form of the line.

$y - y_1 = m(x-x_1)\\y - 0 = 2(x--3)\\y = 2(x+3) \\y = 2x + 6$