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loris [4]
3 years ago
10

Is 1/3x-2y=7 a linear function

Mathematics
1 answer:
Ann [662]3 years ago
5 0

Answer:

The equation is not a linear function.

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What are the solutions to 3n-1 > 8 or 4n+ 3 ​
Mandarinka [93]

Answer:

n>3

Step-by-step explanation:

Step 1: Add 1 to both sides.

3n−1+1>8+1

3n>9

Step 2: Divide both sides by 3.

3n/3>9/3

n>3

3 0
3 years ago
Read 2 more answers
ANSWER IT CORRECTLY FOR BRAINLIEST Amelia built a scale model of a float, using the scale 48:7. The measurements of the actual f
Rashid [163]

Answer:

The third one :)                          

Step-by-step explanation:

6 0
2 years ago
Kate runs 2/3 of a mile on Mondays, Wednesday's and Thursdays. She runs 4/5 of a mile on Tuesday and Fridays. How many miles doe
padilas [110]

Answer:

Therefore, we conclute that Kate run 1 mile and 7/15 of a mile for the week.

Step-by-step explanation:

We know that Kate runs 2/3 of a mile on Mondays, Wednesdays and Thursdays. She runs 4/5 of a mile on Tuesday and Fridays. We calculate how many miles does Kate run during the week.  

Therefore, we get

\frac{2}{3}+\frac{4}{5}=\frac{10+12}{15}=\frac{22}{15}=1+\frac{7}{15}

Therefore, we conclute that Kate run 1 mile and 7/15 of a mile for the week.

8 0
3 years ago
Arun bought a pair of skates at a sale where the discount given was 20%. If the amount he pays is Dhs.4000, find the marked pric
vekshin1
B dhs.3200

because 10% of 4000=400
20%=800
4000-800=3200
4 0
3 years ago
Secants L J and L M intersect and form an angle at point L. Solve for x.
german

Answer:

x = 14  

Step-by-step explanation:

Assume your diagram is like the one below.

The intersecting secant angles theorem states, "When two secants intersect outside a circle, the measure of the angle formed is one-half the difference between the far and the near arcs."

For your diagram, that means

\begin{array}{rcl}m\angle L &=&\dfrac{1}{2} \left(m \widehat {JM} - m\widehat {PQ}\right)\\\\(3x + 13)^{\circ}& = &\dfrac{1}{2} \left[(8x + 48)^{\circ} - (5x - 20)^{\circ}\right]\\\\3x + 13& = &\dfrac{1}{2}(8x + 48 - 5x + 20)\\\\3x + 13& = &\dfrac{1}{2}(3x + 68)\\\\6x + 26 & = & 3x + 68\\6x & = & 3x + 42\\3x & = & 42\\x & = & \mathbf{14}\\\end{array}

Check:

\begin{array}{rcl}(3\times14 + 13) & = &\dfrac{1}{2} \left[(8\times14 + 48)^{\circ} - (5\times14 - 20)^{\circ}\right]\\\\42 + 13& = &\dfrac{1}{2}(112 + 48 - 70 + 20)\\\\55& = &\dfrac{1}{2}(110)\\\\55 & = & 55\\\end{array}

It checks.

6 0
3 years ago
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