Answer:
(-4,-1)
Step-by-step explanation:
Assuming the graph is the one shown in the attachment.
The forward sloping line has a slope of 1 and a y-intercept of 3.
The equation of this line is y=x+3
The horizontal line has a slope of 0 and y-intercept of -1.
It's equation is y=-1
The two lines intersect at (-4,-1)
Let f(x)=y
f^-1(x)=x
y=1/(x+5) - 1
y+1=1/(x+5)
(x+5)=1/(y+1)
x=1/(y+1)-5
f^-1(x)=1/(x+1) -5
denominator cannot equals to zero
x+1≠0
x≠-1
answer
B
Given

We have to set the restraint

because a square root is non-negative, and thus it can't equal a negative number. With this in mind, we can square both sides:

The solutions to this equation are 7 and -2. Recalling that we can only accept solutions greater than or equal to -1, 7 is a feasible solution, while -2 is extraneous.
Similarly, we have

So, we have to impose

Squaring both sides, we have

The solutions to this equation are 5 and 10. Since we only accept solutions greater than or equal to 7, 10 is a feasible solution, while 5 is extraneous.
Answer: The linear equations intersect at 5 , -4
<h2>
Hello!</h2>
The answer is:
The area is equal to 113.04 units.
<h2>
Why?</h2>
To find the area of the circle, we need to use the given information about the radius (6).
So, the area of a circle is given by the following formula:

Where,

Substituting the given radius, we have:

Have a nice day!