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MaRussiya [10]
3 years ago
6

To complete a task in 15 days a company needs 4 people each working for 8 hours per day. the company decides to have 5 people ea

ch working for 6 hours per day. assume that each person works are the same rate. how many days will the task take to complete?
Mathematics
1 answer:
Lilit [14]3 years ago
3 0
It would take 16 days
explanation
if it takes 15 for 4 people to work 8 hours to complete the task, it would be a total of 480 hours. I multiplied 15x4x8. i multiplied 5x6 to get 30. I have to find the third value so i divided 30 from 480 to get 16.
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B) Let g(x) =x/2sqrt(36-x^2)+18sin^-1(x/6)<br><br> Find g'(x) =
jolli1 [7]

I suppose you mean

g(x) = \dfrac x{2\sqrt{36-x^2}} + 18\sin^{-1}\left(\dfrac x6\right)

Differentiate one term at a time.

Rewrite the first term as

\dfrac x{2\sqrt{36-x^2}} = \dfrac12 x(36-x^2)^{-1/2}

Then the product rule says

\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 x' (36-x^2)^{-1/2} + \dfrac12 x \left((36-x^2)^{-1/2}\right)'

Then with the power and chain rules,

\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} + \dfrac12\left(-\dfrac12\right) x (36-x^2)^{-3/2}(36-x^2)' \\\\ \left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} - \dfrac14 x (36-x^2)^{-3/2} (-2x) \\\\ \left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} + \dfrac12 x^2 (36-x^2)^{-3/2}

Simplify this a bit by factoring out \frac12 (36-x^2)^{-3/2} :

\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-3/2} \left((36-x^2) + x^2\right) = 18 (36-x^2)^{-3/2}

For the second term, recall that

\left(\sin^{-1}(x)\right)' = \dfrac1{\sqrt{1-x^2}}

Then by the chain rule,

\left(18\sin^{-1}\left(\dfrac x6\right)\right)' = 18 \left(\sin^{-1}\left(\dfrac x6\right)\right)' \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18\left(\frac x6\right)'}{\sqrt{1 - \left(\frac x6\right)^2}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18\left(\frac16\right)}{\sqrt{1 - \frac{x^2}{36}}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{3}{\frac16\sqrt{36 - x^2}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18}{\sqrt{36 - x^2}} = 18 (36-x^2)^{-1/2}

So we have

g'(x) = 18 (36-x^2)^{-3/2} + 18 (36-x^2)^{-1/2}

and we can simplify this by factoring out 18(36-x^2)^{-3/2} to end up with

g'(x) = 18(36-x^2)^{-3/2} \left(1 + (36-x^2)\right) = \boxed{18 (36 - x^2)^{-3/2} (37-x^2)}

5 0
3 years ago
P = <br> Ok ty please please
Mars2501 [29]

Answer:

p = -15

Step-by-step explanation:

-2 = (p+9)/3 multiply both sides by 3 to get rid of fraction

-6 = p + 9 subtract 9 from both sides

-15 = p

5 0
3 years ago
If you start your break on 08:57 and you have 30 minutes of break when will your break end
VashaNatasha [74]

Answer:

9:27

Step-by-step explanation:

So to get to 9:00, we need 3 minutes so now you have 27 minutes left of break. Then, you add 27 and you get 9:27. I hope this helped and please mark me brainliest!

5 0
3 years ago
Read 2 more answers
Find the volume of a prism whose area of base is 44cmsquare and height is22cm
vovangra [49]
For this problem, you can use the volume of a prism equation:
V=Bh
Where B is the area of the base and h is the height.

So to solve this problem, all you have to do is mutiply 44 square cm by 22 cm.
44 square cm • 22 cm = 968 cubic cm
4 0
3 years ago
What is the value of j(-5)
elena55 [62]

f(x)=\left\{\begin{array}{ccc}2-x&if&x\leq-5\\x+11&if&x > -5\end{array}\right\\\\-5\leq-5\ \text{therefore for}\ x=-5,\ f(x)=2-x\\\\f(-5)=2-(-5)=2+5=7

6 0
4 years ago
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