The answer should be f(x) = 4(x+3) based on your description of slope.<span />
<span>Here you go:
1) Applying (a + b)² = a² + b² + 2ab,
(cosx + cosy)² = cos²x + cos²y + 2cos(x)*cos(y) and
(sinx + siny)² = sin²x + sin²y + 2sin(x)*sin(y)
2) ==> (cosx + cosy)² + (sinx + siny)² =
= (cos²x + sin²x) + (cos²y + sin²y) + 2{cos(x)cos(y) + sin(x)sin(y)}
= 2 + 2{cos(x - y)} = 2[1 + cos(x - y)]
= 2*2cos²{(x - y)/2} [Multiple angle identity, 1 + cos(2A) = 2cos²A]
= 4*cos²{(x - y)/2} [Proved]</span>
Jon ran a total of three miles, since the track was 1/8 of a mile, you had to multiply it with 24/1. 1/8 x 24/1 = 24/8 -> 3 (simplified.)
<u>Answer:</u>
h= 1/4; g = 4
<u>Step-by-step explanation:</u>
1. 3/5h - 1/10 = h/5
First multiply by 10 to get rid of the fractions
(10)3/5h - (10)1/10 = (10)h/5
6h - 1 = 2h
Add one to each side
6h = 2h + 1
Subtract 2h from each side
6h - 2h = 1
4h = 1
Divide 4 by each side
h = 1/4
2. 3g - 10/4 = 1/2
Multiply each side by 4 to get rid of fractions
(4)3g - 10/4 = (4)1/2
3g - 10 = 2
Add 10 to each side
3g = 12
Divide each side by 3
g = 4
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Answer:
a) A=0.86
b) A=2.81
c) A=2.88
Step-by-step explanation:
The average of a functions can be written as:
(1)
a.) The second hour means that the interval of time is from 0 to 2 hours, so a=0 and b=2. Using the equation (1) we can calculate the average intensity.
Using integration by parts we can solve it.
, 
, 
(2)
Therefore, the average intensity at the second hour will be:
b) We can use the equation (2) to solve it. In this case the limits of integration will be a = 0 and b = 12 hours.
Therefore, the average intensity at the twelfth hour will be:
c) Finally, here a = 0 and b = 24 hour.
Therefore, the average intensity at the twenty-fourth hour will be:
I hope it helps you!
