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AURORKA [14]
3 years ago
10

Solve the system by substitution!

Mathematics
1 answer:
irga5000 [103]3 years ago
3 0
When solving by substation the answer would be: X= 1 , y= 5
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Find the value of x, which makes the area of this triangle equal 72.
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Area of a triangle=1/2(base x height)
Area=72, Base=8, Height=2x-3
Plug it in.
72=1/2(8 x (2x-3))
72=1/2(16x-24)
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If you are doing a multi step question that looks something like this: 23+(4)-4 or longer. You will have to use a formula called BEDMAS. It stands for brackets, exponents( which are little numbers on top of a number), then you deal with division, multiplication, addition, and subtraction. You will have to solve your equation in this order. If you don’t you will get another, answer.
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What is the equation of the line that passes through the point (9, 6) and is perpendicular to the line y = 3x - 5?
Ilia_Sergeevich [38]

Answer:

Step-by-step explanation:

y = 3x - 5

m₁ = 3

The required line is perpendicular to y = 3x - 5. Let the required line's slope be m₂

m₂ = -1/m₁

m₂ = -1/3

Point (9,6)

Equation of line: y - y₁ = m(x - x₁)

y - 6 = (-1/3)(x - 9)

y-6=\frac{-1}{3})x+\frac{1}{3}*9\\\\y-6=\frac{-1}{3}x+3\\\\y=\frac{-1}{3}x+3+6\\\\y=\frac{-1}{3}x+9\\

5 0
3 years ago
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar.
Anika [276]

Answer:

\large\boxed{y=\dfrac{1}{2}x^2-2x+1}

Step-by-step explanation:

The vertex form of an equation of a parabola:

y=a(x-h)^2+k

<em>(h, k)</em><em> - vertex</em>

<em>a</em><em> - leading coefficient in equation </em><em>y = ax² + bx + c</em>

<em />

From the grap we can read coordinates of the vertex (2, -1) and y-intercept (0, 1).

Therefore <em>h = 2, k = -1</em>

Put the values of <em>h, k</em> and coordinates of the y-intercept to the equation of parabola:

1=a(0-2)^2-1     <em>add 1 to both sides</em>

1+1=a(2)^2-1+1

2=4a              <em>divide both sides by 4</em>

\dfrac{2}{4}=\dfrac{4a}{4}\\\\\dfrac{1}{2}=a\to a=\dfrac{1}{2}

Therefore we have the equation:

y=\dfrac{1}{2}(x-2)^2-1

Convert to the standard form:

y=\dfrac{1}{2}(x-2)^2-1       <em>use (a - b)² = a² - 2ab + b²</em>

y=\dfrac{1}{2}(x^2-2(x)(2)+2^2)-1

y=\dfrac{1}{2}(x^2-4x+4)-1           <em>use the distributive property</em>

y=\dfrac{1}{2}x^2-\dfrac{1}{2}\cdot4x+\dfrac{1}{2}\cdot4-1

y=\dfrac{1}{2}x^2-2x+2-1          <em>combine like terms</em>

y=\dfrac{1}{2}x^2-2x+1

5 0
3 years ago
The perimeter of a right angled
Artemon [7]
A=3cm
or
4cm
P Perimeter

cm
A Area

cm²
7 0
2 years ago
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