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yan [13]
3 years ago
15

Hilda has $210 worth of $10 and $12 stock shares. The number of $10 shares is five more than twice the number of $12 shares. How

many of each type of share does she have?

Mathematics
2 answers:
djverab [1.8K]3 years ago
7 0

Answer:

15 | 10-dollar shares, 5 | 12- dollar shares

Step-by-step explanation:

Write the equation by adding the total values of each type of share.

10(2t+5)+12t=210

We can solve this equation for t to find the number of $12 shares.

10(2t+5)+12t=210

20t+50+12t=210

32t=160

t=5

So, the number of $12 shares is 5. Since the number of $10 shares is 5 more than twice the number of $12 shares, the number of $10 shares is 2(5)+5=15.

Hilda bought 5 $12 shares and 15 $10 shares.

klasskru [66]3 years ago
6 0
Let's first define variables.
 y: number of shares of $ 10
 x: number of shares of $ 12
 We write the system of equations:
 10x + 12y = 210
 y = 2x + 5
 Solving the system:
 x = 75/17
 y = 235/17
 Answer: 
 she has: 
 75/17 shares of $ 12 
 235/17 shares of $ 10

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Hope this helps! :)

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75% as a fraction in simplest form
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3/4

Step-by-step explanation:

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5 0
3 years ago
72
Zigmanuir [339]

Answer:

Ai. Arithmetic sequence

Aii. Tn = 5 + 7n

Bi. Geometric

Bii. Tn = 8 × 2ⁿ¯¹

Step-by-step explanation:

To successfully answer the questions given above, note the following:

1. If the sequence is Arithmetic, then:

2nd – 1st = 3rd – 2nd = common difference (d)

2. If the sequence is geometric, then,

2nd / 1st = 3rd / 2nd = common ratio (r)

3. A sequence can not be arithmetic geometric at the same time.

4. The nth term of arithmetic sequence is:

Tn = a + (n – 1)d

5. The nth term of geometric sequence is:

Tn = arⁿ¯¹

A. Sequence => 12, 19, 26

i. Determination of the type of sequence.

We'll begin by calculating the common difference

1st term = 12

2nd term = 19

3rd term = 26

Common difference (d) = 2nd – 1st

d = 19 – 12 = 7

OR

d = 3rd – 2nd

d = 26 – 19 = 7

Since a common difference exist in the sequence, the sequence is arithmetic sequence.

ii. Determination of the nth term.

Common difference (d) = 7

1st term (a) = 12

nth term (Tn) =?

Tn = a + (n – 1)d

Tn = 12 + (n – 1)7

Tn = 12 + 7n – 7

Tn = 5 + 7n

B. Sequence => 8, 16, 32

Bi. Determination of the type of sequence.

Let us begin by calculating the common ratio.

1st term = 8

2nd term = 16

3rd term = 32

Common ratio (r) = 2nd / 1st

r = 16 / 8

r = 2

OR

r = 3rd / 2nd

r = 32 / 16

r = 2

Since a common ratio exist in the sequence, the sequence is geometric.

Bii. Determination of the nth term.

Common ratio(r) = 2

1st term (a) = 8

nth term =?

Tn = arⁿ¯¹

Tn = 8 × 2ⁿ¯¹

8 0
3 years ago
A triangle has points R(-2,0) ,S(2,8) and T (8,2) as shown in the group. M is the midpoint of RT . What is the length of SM
wlad13 [49]

The midpoint is calculated by averaging the coordinates of its endpoints:

M = \left(\dfrac{-2+8}{2},\dfrac{0+2}{2}\right)=(3,1)

Now we can use the usual distance formula to get the length of SM:

SM=\sqrt{(2-3)^2+(8-1)^2}=\sqrt{1+49}=\sqrt{50}

5 0
4 years ago
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