3 years ago

Evaluate 13-0.5w+6x when w=10 and x=1/2

2 answers:

6 0

Ok so first you need to put w and x in the equation —-> 13-0.5(10)+6(1/2) and now you just solve -0.5 times 10 is -5 so 13-(-5)+6(1/2) now multiply 6 times 1/2 which is 3 so now we have 13-(-5)+3= 21

IrinaK [193]3 years ago

3 0

Answer:

Step-by-step explanation:

13-0.5w+6x

13-0.5(10)+6(1/2)

13-5+6/2

8+3

You might be interested in

Don’t get it please helppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppp

UNO [17]

What do you don’t get

7 0

3 years ago

The Campers in cabin D walked 1/6 of the way to Mammoth Mountain. how many miles did the walk ?

svet-max [94.6K]

What is the question ?

4 0

3 years ago

Noah planned a parallelogram-shaped sidewalk to lead from the street to the front door of his house. He realized the walkway was

nekit [7.7K]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

The rectangle below has an area of 70y^8+30y^6.The width of the rectangle is equal to the greatest common monomial factor of 70y

swat32

Answer:

Width $10y^6$ units

Length $7y^2+3$ units

Step-by-step explanation:

The rectangle has an area of $70y^8+30y^6.$

The width of the rectangle is equal to the greatest common monomial factor of $70y^8$ and $30y^6.$ Find this monomial factor:

$70y^8=2\cdot 5\cdot 7\cdot y^8\\ \\30y^6=2\cdot 3\cdot 5\cdot y^6\\ \\GCF(70y^8,30y^6)=2\cdot 5\cdot y^6=10y^6$

Hence, the width of the rectangle is $10y^6$ units.

The area of the rectangle can be rewritten as

$10y^6(7y^2+3).$

The area of the rectangle is the product of its width by its length, then the length of the rectangle is $7y^2+3$ units.

8 0

3 years ago

Square one factor from column A and add it to one factor from column B to develop your own identity. (image attached) 60 points

Tamiku [17]

Answer:

x^4+64 = x^2 -4x+8 * x^2 +4x+8

Step-by-step explanation:

6 0

3 years ago