Answer: = 3.1; this pond can expect the difference of frogs and koi to vary by approximately 3.1 from the mean.
Step-by-step explanation:
Answer
-sqrt(18)<x<sqrt(18)
Step-by-step explanation:
- Factorise:(x-sqrt(18))(x+sqrt(18))<0
- Critical values:-sqrt18 and sqrt18
- Use number line or graphical method
I dont believe there are any