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polet [3.4K]
3 years ago
10

Show all work to solve by factoring 3x^2 − x − 2 = 0.

Mathematics
1 answer:
shtirl [24]3 years ago
4 0

Answer:

The solutions are x=1 and x=-2/3

Step-by-step explanation:

we have

3x^{2}-x-2=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

3x^{2}-x=2

Factor the leading coefficient

3(x^{2}-(1/3)x)=2

Complete the square. Remember to balance the equation by adding the same constants to each side

3(x^{2}-(1/3)x+(1/36))=2+(1/12)

3(x^{2}-(1/3)x+(1/36))=25/12

Rewrite as perfect squares

3(x-(1/6))^{2}=25/12

(x-(1/6))^{2}=25/36

square root both sides

(x-(1/6))=(+/-)(5/6)

x=(1/6)(+/-)(5/6)

x=(1/6)(+)(5/6)=1

x=(1/6)(-)(5/6)=-2/3

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you sold brownies for $3 each.You sold 14 more this week than last week altogether. You made $84. how many brownies did you sell
Luba_88 [7]

Answer: 8

Step-by-step explanation: Altogether you sold x last week, if you do x + 14 which is 2x12 brownies sold, then at 3$ each 3(2x+12)=84 so 6x + 36 = 84

84- 36 = 48/6 = 8

7 0
3 years ago
After arianna completed some work, she figured she still had 78 21/100 pictures to paint. if she completed another 34 23/25 pict
dezoksy [38]

Subtract the number she completed from what she had left to paint originally.

The fractions have different denominators so first step is to rewrite the fractions with a common denominator.

23/25 can be rewritten as 92/100

Now you have 78 21/100 - 34 92/100

Because 21/100 is smaller than 92/100 subtract 1 whole number from 78 and rewrite 1 as 100/100 and add that to the fraction.

78 21/100 becomes 77 121/100

Now subtract :

77 121/100 - 34 92/100

77-34 = 43

And 121/100 - 92/100 = 29/100

Combine to get 43 and 29/100

3 0
3 years ago
Please help!!! I am so confused!
Dafna11 [192]
The first one is c because if you put it at negative 1/8 then it is 0-1/8 or 1/8 away from zero

second one is
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3 0
3 years ago
Read 2 more answers
15x^2 + 41x + 28 <br><br>STEP BY STEP ANSWER PLSSS​
maria [59]

Answer:

(3x+4)(5x+7)

Step-by-step explanation:

15x^2 +41x+28

Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2 +ax+bx+28. To find a and b, set up a system to be solved.

a+b=41

ab=15×28=420

Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.

1,420

2,210

3,140

4,105

5,84

6,70

7,60

10,42

12,35

14,30

15,28

20,21

Calculate the sum for each pair.

1+420=421

2+210=212

3+140=143

4+105=109

5+84=89

6+70=76

7+60=67

10+42=52

12+35=47

14+30=44

15+28=43

20+21=41

The solution is the pair that gives sum 41.

a=20

b=21

Rewrite 15x^2 +41x+28 as (15x^2 +20x)+(21x+28).

(15x^2 +20x)+(21x+28)

Factor out 5x in the first and 7 in the second group.

5x(3x+4)+7(3x+4)

Factor out common term 3x+4 by using distributive property.

(3x+4)(5x+7)

7 0
3 years ago
Read 2 more answers
What where William total fixed variable expenses the first year of college
VARVARA [1.3K]

Since the details are not available, we have provided an overview of William's total fixed and variable expenses for the first year of college.

<h3>What are college costs?</h3>

There are five categories of college costs.

These college costs include tuition, room and board, books and supplies, personal expenses, and transportation.

Some of the college costs like tuition and room and board may be relatively fixed.

This leaves expenses like books and suppliers, personal expenses, and transportation relatively variable.

Thus, William needs to control his variable college costs so that they do not exceed the student loan.

Learn more about college costs at brainly.com/question/11650418

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