Answer: 8
Step-by-step explanation: Altogether you sold x last week, if you do x + 14 which is 2x12 brownies sold, then at 3$ each 3(2x+12)=84 so 6x + 36 = 84
84- 36 = 48/6 = 8
Subtract the number she completed from what she had left to paint originally.
The fractions have different denominators so first step is to rewrite the fractions with a common denominator.
23/25 can be rewritten as 92/100
Now you have 78 21/100 - 34 92/100
Because 21/100 is smaller than 92/100 subtract 1 whole number from 78 and rewrite 1 as 100/100 and add that to the fraction.
78 21/100 becomes 77 121/100
Now subtract :
77 121/100 - 34 92/100
77-34 = 43
And 121/100 - 92/100 = 29/100
Combine to get 43 and 29/100
The first one is c because if you put it at negative 1/8 then it is 0-1/8 or 1/8 away from zero
second one is
the
reciprocal is the number that when multiiplied by the number you are
trying to find the reciprocal of, you get +1 so the number you have is
2/7 so
2/7 times x=+1
multiply both sdies by 7/2 to clear fraction
x=+7/2
the reciprocal is +7/2 or +3 and 1/2 which is D
Answer:
(3x+4)(5x+7)
Step-by-step explanation:
15x^2
+41x+28
Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2
+ax+bx+28. To find a and b, set up a system to be solved.
a+b=41
ab=15×28=420
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.
1,420
2,210
3,140
4,105
5,84
6,70
7,60
10,42
12,35
14,30
15,28
20,21
Calculate the sum for each pair.
1+420=421
2+210=212
3+140=143
4+105=109
5+84=89
6+70=76
7+60=67
10+42=52
12+35=47
14+30=44
15+28=43
20+21=41
The solution is the pair that gives sum 41.
a=20
b=21
Rewrite 15x^2
+41x+28 as (15x^2
+20x)+(21x+28).
(15x^2
+20x)+(21x+28)
Factor out 5x in the first and 7 in the second group.
5x(3x+4)+7(3x+4)
Factor out common term 3x+4 by using distributive property.
(3x+4)(5x+7)
Since the details are not available, we have provided an overview of William's total fixed and variable expenses for the first year of college.
<h3>What are college costs?</h3>
There are five categories of college costs.
These college costs include tuition, room and board, books and supplies, personal expenses, and transportation.
Some of the college costs like tuition and room and board may be relatively fixed.
This leaves expenses like books and suppliers, personal expenses, and transportation relatively variable.
Thus, William needs to control his variable college costs so that they do not exceed the student loan.
Learn more about college costs at brainly.com/question/11650418
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