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3 years ago

How can I use the Distributive Property to answer 144 -:- 8??

1 answer:

6 0

Distributive property of division is that the division of a sum equals the division of the summands.
Algebraically, this is:
[x + y + z] / a = x/a + y/a + z/a.
So, applying this to 144 / 8, you can split 144 as [72 + 32 + 40] / 8 = 72/8 + 32/8 + 40/8 = 9 + 4 + 5 = 18

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Determine the number of terms in the sequence: –45, –32, –19, –6, ..., 124.

stiks02 [169]

Step-by-step explanation:

$- 32 + 45 = 13 \\ t_{n} = ( a_{1} + (n - 1)d) \\ \\ d = 13 \: \: a_{1} = - 45$

$t_{n} = - 45 + (n - 1)13 = = = > \\ - 45 + 13n - 13 = = = > \\ t_{n} = 13n - 58$

and now

$124 = 13n - 58 = = = > \\ 182 = 13n = = = > n = 14$

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2 years ago

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What is a reciprocal of 9 1/4

strojnjashka [21]

9 1/4
= 37/4

Therefore the reciprocal will just be the inverse which is...

=4/37

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4 years ago

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A buyer went to the market to buy strawberries. He purchased 120 randomly selected strawberries from a vendor who claimed that n

mafiozo [28]

Answer:

$z=\frac{0.333 -0.25}{\sqrt{\frac{0.25(1-0.25)}{120}}}=2.10$

$p_v =P(z>2.10)=0.018$

At 5% of significance we can conclude that the true proportion of strawberries damage is higher than 0.25

Step-by-step explanation:

Data given and notation

n=120 represent the random sample taken

X=40 represent the number of strawberries damaged

$\hat p=\frac{40}{120}=0.333$ estimated proportion of strawberries damaged

$p_o=0.25$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that no more than 25% of his total harvest of strawberries was damaged.:

Null hypothesis: $p\leq 0.25$

Alternative hypothesis: $p > 0.25$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.333 -0.25}{\sqrt{\frac{0.25(1-0.25)}{120}}}=2.10$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>2.10)=0.018$

At 5% of significance we can conclude that the true proportion of strawberries damage is higher than 0.25

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3 years ago

Describe and correct the error below.

RUDIKE [14]

Answer:

Software comprises the entire set of programs, procedures, and routines associated with the operation of a computer system. The term was coined to differentiate these instructions from hardware—i.e., the physical components of a computer system.

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3 years ago

WOODLL PUNTO. CU

viktelen [127]

Answer:

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Step-by-step explanation:

Set up the equations.

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