Can someone please help me??
2 answers:
Answer:
b=3, y=6
Step-by-step explanation:
Label the 2 equations:
2b +6y= 42 -----(1)
2b +4y= 30 -----(2)
(1) -(2):
(2b +6y) -(2b +4y)= 42 -30
2b +6y -2b -4y= 12
2y= 12
y= 12 ÷2 <em>(</em><em>÷</em><em>2</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>
y= 6
Susbt. y=6 into (2):
2b +4(6)= 30
2b +24=30
2b= 30 -24 <em>(</em><em>-24</em><em> </em><em>on</em><em> </em><em>b</em><em>o</em><em>t</em><em>h</em><em> </em><em>sides</em><em>)</em>
2b= 6
b= 6 ÷2
b= 3
Answer:
y = 6, b = 3
Step-by-step explanation:
Since both equations have 2b in them, subtracting them gets you a quick result because the 2b-2b cancels out!
2b + 6y = 42
2b + 4y = 30
------------------ -
2y = 12
y = 6
Then 2b = 42 - 36 = 6, so b = 6/2 = 3
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Step-by-step explanation:
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