Using: loga b = log b / log a
1) a=x+3, b=4 → y1=log4 (x+3) → y1= log (x+3) / log 4
2) a=2+x, b=2 →y2=log2 (2+x) → y2=log (2+x) / log 2
Answer:
y1=log (x+3) / log 4, y2= log (2+x) / log 2
Answer:
14 miles.
Step-by-step explanation:
Let the distance traveled from home to destination = x miles.
Speed while going to friend's house = 35 miles per hour.
Speed while coming back = 40 miles per hour.
Total Time taken for the journey = 45 minutes = 0.75 hours.
Let the time taken while going to friend's house = y hours.
Therefore, the time taken while going to friend's house = (0.75 - y) hours.
To find x and y, model the speeds of both the journeys.
Speed while going to friend's house = Distance/Time.
35 = x/y.
x = 35y (Equation 1).
Speed while coming back = Distance/Time.
40 = x/(0.75 - y).
x = 40(0.75 - y) (Equation 2).
Since x = x, therefore:
35y = 30 - 40y.
75y = 30.
y = 30/75.
y = 0.4 hours.
Put y = 0.4 hours in Equation 1:
x = 35y.
x = 35(0.4).
x = 14.
Therefore, the distance between my friend's house and my house is 14 miles!!!
Answer:
I got 6.012 times 10^3
Step-by-step explanation:
I'm not sure how to make it into decimal form but maybe that number can help you. Hopefully it's correct
C. 6 2/12 because you put the common denominator (12) by multiplying 1/4 x 3/3 then add it to get 5 14/12 or 6 2/12
D.5 2/15
