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maksim [4K]
3 years ago
15

What is 9/3 as a fraction?

Mathematics
2 answers:
Harrizon [31]3 years ago
7 0
9/3 is a fraction, but an improper fraction. As a mixed fraction it would be 2and2/3.
Hope this helps!
koban [17]3 years ago
4 0
9/3 is already made a fraction.

Why?

Because it is not a whole numer.

Well, this improper fraction can be simplified.

<u>9 </u>  ÷ 3<u>
</u>3    ÷ 3

= 1.
<u />
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Can someone help me with this one
bonufazy [111]

Answer:

x(2x+1)(x-2)

Step-by-step explanation:

x(2x^2-3x-2)

x(2x^2-4x+x-2)

x[2x(x-2)+1(x-2)]

x(2x+1)(x-2)

3 0
3 years ago
Find the axis of summetry and the Vertex of its graph. Y=x2/squared-8x
Vilka [71]

Answer:

Direction: Opens Up

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Axis of Symmetry:

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xy2-143-174-185-176-14

Graph the parabola using its properties and the selected points.

Direction: Opens Up

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image of graph

3 0
3 years ago
A maple tree in the backyard of a home has a height of 0.75 meters. How many times as tall (t) is a nearby hickory tree that is
anygoal [31]

Answer: 12

Step-by-step explanation:

Since we are informed that a maple tree in the backyard of a home has a height of 0.75 meters.

To know the jow many times tall (t) is a nearby hickory tree that is 9 meters tall, we've to divide the height of the hickory tree by the height of the maple tree. This will be:

= 9meters / 0.75meters

= 12

Therefore, the hickory tree is 12 times tall as the maple tree.

4 0
3 years ago
GUYS HELP PLEASE URGENT!!!!!!
kkurt [141]
Well that would equate to 3136. So I would guess grams.
8 0
3 years ago
Read 2 more answers
A 15-ft ladder rests against a vertical wall. If the top of the ladder slides down the wall at a rate of 0.33 ft/sec, how fast,
3241004551 [841]

Answer:

0.44 ft/sec.

Step-by-step explanation:

Let A is the bottom of the ladder and AB is the distance from the bottom of the wall i.e. B is the bottom of the wall. If C is the top of the ladder and BC is the height of the wall.

Now, Δ ABC is a right triangle and AC is the length of the ladder i.e. hypotenuse.

Now, AC² = AB² + BC² {From Pythagoras Theorem}

Now, differentiating both sides with respect to time t, we get

0 = 2 \times (AB) \times \frac{d(AB)}{dt} +  2 \times (BC) \times \frac{d(BC)}{dt}

⇒  \frac{d(AB)}{dt} = - \frac{BC}{AB} \times  \frac{d(BC)}{dt}

Now, given that \frac{d(BC)}{dt} = - 0.33 feet/sec.

Hence, \frac{d(AB)}{dt} = - \frac{BC}{AB} \times  (- 0.33) ......... (1)

Now, given that AB = 9 ft. and AC = 15 ft.

So, 15² = 9² + BC²  

⇒ BC² = 144

⇒ BC = 12 feet.

Now, from equation (1), we get

\frac{d(AB)}{dt} = - \frac{12}{9} \times  (- 0.33) = 0.44

Therefore, the bottom of the ladder is sliding away from the wall at the rate of 0.44 ft/sec. (Answer)

3 0
3 years ago
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