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s2008m [1.1K]
3 years ago
9

My first expression answer is y=5 -2x How do I plug it into x-y=1 ?? The Y

Mathematics
1 answer:
Lemur [1.5K]3 years ago
8 0

Answer:

All you need to do is make sure the first expression is solved for y (which it is), and then substitute it into the second expression in place of any occurrences of y:

given the second expression:

x - y = 1

We'll replace y with it's value in the first expression:

x - (y) = 1

x - (5 - 2x) = 1

Now we can expand the resulting equation:

x - 5 + 2x = 1

So <em>neither</em> of the answers provided are correct.

You can then solve for x:

x - 5 + 2x = 1

x - 5 + 5 + 2x = 1 + 5

x + 2x = 6

3x = 6

3x/3 = 6/3

x = 2

After that, you can find y by plugging x into either of the two original equations:

y = 5 - 2x

y = 5 - 2(2)

y = 5 - 4

y = 1

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What is the length of the hypotenuse triangle if both sides are 36
vovikov84 [41]

Answer:

<h3>\boxed{ \bold{ \huge{ \boxed{ \sf{36 \sqrt{2}  \:  \:  units}}}}}</h3>

Step-by-step explanation:

Given,

Perpendicular ( P ) = 36

Base ( b ) = 36

Hypotenuse ( h ) = ?

<u>Finding</u><u> </u><u>the </u><u>hypotenuse </u> :

<u>Using </u><u>the </u><u>Pythagoras </u><u>theorem</u><u> </u>:

\sf{ {h}^{2}  =  {p}^{2}  +  {b}^{2} }

plug the values

⇒\sf{ {h}^{2}  =  {36}^{2}  +  {36}^{2} }

Evaluate the power

⇒\sf{ {h}^{2}  = 1296 + 1296}

Add the numbers

⇒\sf{ {h}^{2}  = 2592}

Squaring on both sides

⇒\sf{h = 36 \sqrt{2} } units

Hope I helped!

Best regards!!

7 0
3 years ago
What is the range of y=−x^2−2x+3?<br><br> x≤−4<br><br> x≤4<br><br> x≥−4<br><br> x≥4
saveliy_v [14]

Answer:

Domain: (−∞,∞),{x|x∈R}

Range: (−∞,4],{y|y≤4

Hope this helps

4 0
4 years ago
Please please help me please
MAVERICK [17]

Answer:

1st option is the answer

Step-by-step explanation:

blue line:  slope is 1 and y-intercept is 1; therefore equation is y= x + 1

red line:  slope is -1 and y-intercept is -3; therefore equation is y= -x - 3

7 0
3 years ago
Simply the imaginary number square root -45
Paraphin [41]

Answer:

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Step-by-step explanation:

Using the rule of radicals

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and \sqrt{-1} = i

Given

\sqrt{-45}

= \sqrt{9(5)(-1)}

= \sqrt{9} × \sqrt{5} × \sqrt{-1}

= 3 × \sqrt{5} × i

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6 0
3 years ago
Select the correct answer.
Leni [432]
The answer is 25.
Have a good night
4 0
3 years ago
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