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mash [69]
3 years ago
15

Find the 32nd term of the sequence 34, 37, 40, 43

Mathematics
2 answers:
lukranit [14]3 years ago
7 0
The answer would be 127 the pattern is +3
Triss [41]3 years ago
6 0
Increases by 3 each time
aritmetic sequence, firsrt term is 34, 3=common differnce
an=a1+d(n-1) is da formlua
a1=first term
d=common differnce
an=34+3(n-1)
so 32n'd term is
a32=34+3(32-1)
a32=34+3(31)
a32=34+93
a32=127
the 32nd term is 127
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