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2 years ago

Positive square root of 29584

2 answers:

8 0

Positive square root of 29584.

√29584 = ?
√29584 = 172

Check:
172² = ?
172² = 172 × 172 = 29584
172² = 29584
Correct!

Postie square root of 29584 is 172.
√29584 = 172

Amanda [17]2 years ago

7 0

√29584 = √(2⁴·43²)
= (√2⁴)(√43²)
= 2²·43
= 172

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Kelvin saves $60 a day. Al saves $90 a day. How many times Kelvin's savings are Al's savings?

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3 years ago

Read 2 more answers

The formula for finding the perimeter of a rectangle is P = 2L + 2W. If a rectangle has a perimeter of 68 inches and the length

Artemon [7]

Answer:

Width = 10 inches

Step-by-step explanation:

Given the perimeter of a rectangle of 68 inches, and a length that is 14 inches longer than its width.

We can establish the following values to help us solve for the width of a rectangle:

Perimeter (P) = 68 inches

Length (L) = 14 + W inches

Width (W) = unknown

<h3 /><h3><u>Solve for the Width (W)</u></h3>

P = 2(L + W) ⇒ This is the same as P = 2L + 2W, except that 2 is factored out from the right-hand side.

Divide both sides by 2:

$\displaystyle\mathsf{\frac{P}{2}\:=\:\frac{2(L\:+\:W)}{2}}$

$\displaystyle\mathsf{\frac{P}{2}\:=L\:+\:W}$

Substitute the value of the Perimeter and the length (L) into the formula:

$\displaystyle\mathsf{\frac{68}{2}\:=14\:+W\:+\:W}$

Combine like terms on the right-hand side, and simplify the left-hand side of the equation:

$\displaystyle\mathsf{34\:=14\:+2W}$

Subtract 14 from both sides:

34 - 14 = 14 - 14 + 2W

20 = 2W

Divide both sides by 2 to solve for the width (W):

$\displaystyle\mathsf{\frac{20}{2}\:=\:\frac{2W}{2}}$

W = 10 inches

Therefore, the width of the rectangle is 10 inches.

<h3 /><h3><u>Double-check:</u></h3>

Verify whether the derived value for the width is correct:

P = 2L + 2W

68 = 2(14 + 10) + 2(10)

68 = 2(34) + 20

68 = 48 + 20

68 = 68 (True statement).

Thus, the length of the rectangle is 34 inches, and the width is 10 inches.

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2 years ago

What is the inverse of the function?<br> f(x) = 1/3x-5

OlgaM077 [116]

Answer:

-1

f (x) = -3(x + 5)

Step-by-step explanation:

1) in f(x) = 1/3x-5, replace f(x)= with y= as follows: y = (1/3)x - 5

2) interchange x and y, obtaining: x = (1/3)y - 5

3) solve this result for y: (1/3)y = -x - 5, or -(x + 5). Next, multiply both sides by 3 to eliminate the fraction (1/3): y = -3(x + 5)

4) replace y with the symbol for "inverse of f(x);

-1

f (x) = -3(x + 5)

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3 years ago

True or false? A correct answer is worth (2 pts). Explain how you know for the additional (2 pts). Using complete sentence for (

PtichkaEL [24]

<u>answer (in words)</u>

FALSE. the coordinate pair (5, 2) is not a solution to the equation $2x+3y=10$ . in order to figure out whether or not the statement is true or false, plug the $x$ and $y$ values from the coordinate pair (5, 2) into the given equation, $2x+3y=10$ . if both sides of the equation end up equal, the coordinate pair is a solution to the equation. if not, the coordinate pair is not a solution to that equation.

<em>(i hope i explained that well enough, i'm better at explaining it algebraically as opposed to putting it into words lol)</em>

<u>answer (algebraic/steps for solving)</u>

first, plug in 5 for $x$ in the equation $2x+3y=10$ .

$2x+3y=10$ ⇒ $2(5)+3y=10$

then plug in 2 for $y$ .

$2(5)+3y=10$ ⇒ $2(5)+3(2)=10$

now your equation is $2(5)+3(2)=10$ . all that's left to do is to simplify. you can do this in whatever order you'd like, but i'll start with multiplying 2 · 5.

$2(5)+3(2)=10$ ⇒ $10 + 3(2) = 10$

multiply 3 · 2.

$10 + 3(2) = 10$ ⇒ $10 + 6 = 10$

add 10 + 6.

$10 + 6 = 10$ ⇒ $16=10$

16 and 10 are <em>not</em> equal, therefore (5, 2) is not a solution to the equation $2x+3y=10$ . in order for a coordinate pair to be the solution to an equation, both sides of the equation need to end up equal after solving and simplifying.

i hope this helps! have a great rest of your day <3

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2 years ago

Line segment AB has vertices A(-3, 4) and B(1, -2). A dilation centered at the orgin is applied to AB. The image has vertices A(

bixtya [17]

Answer:

option 2

Step-by-step explanation:

consider the coordinates A (- 3, 4 ) and A' (- 1, $\frac{4}{3}$ )

since the dilatation is centred at the origin, then corresponding coordinates are multiples/ divisors of each other, then image to original gives scale factor.

scale factor = $\frac{A'}{A}$ = $\frac{-1}{-3}$ = $\frac{1}{3}$ and $\frac{\frac{4}{3} }{4}$ = $\frac{1}{3}$

similarly B (1, - 2 ) and B' ( $\frac{1}{3}$ , - $\frac{2}{3}$ )

$\frac{\frac{1}{3} }{1}$ = $\frac{1}{3}$ and $\frac{-\frac{2}{3} }{-2}$ = $\frac{1}{3}$

4 0

1 year ago