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Luba_88 [7]
3 years ago
12

3. Factor.

Mathematics
1 answer:
sleet_krkn [62]3 years ago
5 0
It seems that some the work is already here, but I'd be glad to!! So for #3 which is 9x^2+15x, we can factor out both a 3 and an x (3x) so we know that 3x * 3x =9x^2 and 3x * 5 = 15x so once we take the 3x out of the equation, we are left with 3x(3x+5) and that's as far as you can factor.
For #4, we see that the common factor is 10m because 10m * 2n = 20mn and 10m * 3 = 30m so once we take 10m out of the original, it becomes 10m(2n-3)
For #5, this one the common factor is 4xy because 4xy * 2xy=8x^2y^2 and 4xy*x= 4x^2y and 4xy*3=12xy so once we take the 4xy out of the equation, it becomes 4xy(2xy-x-3)
Hope this helps!
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<u>Step 1:  Find the answer </u>

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3 0
2 years ago
In the picture below and show steps or explain
telo118 [61]

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7 0
2 years ago
Read 2 more answers
Solve for x give answer as radicals (roots)
skelet666 [1.2K]

Answer:

x = 15

Step-by-step explanation:

Use pythagorean theorem: a^{2} +b^{2} = c^{2}

8^{2} +x^{2} =17^{2} \\ 64 + x^{2} = 289 \\\\x^{2} = 289 - 64\\x^{2} = 225\\x = 15

8 0
3 years ago
The polynomial x 3 + 5x 2 - ­57x -­189 expresses the volume, in cubic inches, of a shipping box, and the width is (x+3) in. If t
Ipatiy [6.2K]
V=x^3+5x^2-57x-189
Width: W=(x+3) in = 15 in →x+3=15
Solving for x:
x+3-3=15-3→x=12

With x=12 the Volume would be:
V=(12)^3+5(12)^2-57(12)-189
V=1,728+5(144)-684-189
V=1,728+720-684-189
V=1,575

V=W*D*H
Depth: D
Height: H
with H>D

V=1,575; W=15
Replacing in the equation above:
1,575=15*D*H
Dividing both sides by 15
1,575/15=(12*D*H)/15
105=D*H
3*5*7=D*H
D<H
If D=5→H=3*7→H=21
If D=7→H=3*5→H=15

Answer: Option <span>C. height: 21 in. depth: 5 in.
</span>
Please, see the attached file for another form to solve the problem

4 0
3 years ago
Read 2 more answers
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