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Amanda [17]
3 years ago
6

The slope of the line below is 1.write the point-slope equation for the line using the coordinates of the labeled point.

Mathematics
1 answer:
Oliga [24]3 years ago
5 0

Answer:

y-4=(x-11) or y=(x-11)+4

Step-by-step explanation:

We know that the slope of the line is 1, so we can write it in terms of any two points belonging to the line, as per the difinition of slope:

slope=\frac{y_1-y_0}{x_1-x_0} \\1=\frac{y_1-y_0}{x_1-x_0}

We can use instead of (x_1,y_1) any general point (x,y) on the line, and for (x_0,y_0) the point we are interested in: (11,4)

That way the slope can be written as:

1=\frac{y-4}{x-11}

Next we can solve for y if this format is the one your instructor prefers:

1=\frac{y-4}{x-11}\\1(x-11)=(y-4)\\(x-11)+4 =y

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Which statement is true about the extreme value of the given quadratic equation? y = -3x2 + 12x − 33
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Answer:

The equation has a maximum value with a y-coordinate of -21.

Step-by-step explanation:

Given

y =-3x^2 + 12x - 33

Required

The true statement about the extreme value

First, write out the leading coefficient

Leading = -3

-3 < 0 means that the function would be a downward parabola;

Downward parabola always have their vertex on top of the parabola and as such, the function has a maximum value.

The maximum value is:

x = -\frac{b}{2a}

Where:

a= -3; b =12; c =-33

So, we have:

x = -\frac{12}{2 * -3}

x = -\frac{12}{-6}

x =2

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y = -3*2^2 + 12 * 2 - 33

y = -21

<em>Hence, the maximum is -21.</em>

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