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iren [92.7K]
3 years ago
12

Approximately how many times greater is 1.2×103 than 4×10−1 ?

Mathematics
1 answer:
Galina-37 [17]3 years ago
4 0
3000 Quick answer
Let your calculator do the work. Be careful how you enter this in. (Are you supposed to estimate it? We'll get around to that.) Write it like this.

1.2 * 10^3 divided by 4 * 10^-1 Your calculator will do this nicely. The trick is the - 1. Put it in the calculator like this.
1.2 
*
10
^
3
=
÷
4
*
10
^
(-1) 
= The calculator should read 3000
That's one way to do it. Another way is just to do it all by hand. The numbers are easy enough
1.2 * 10^3 means shift the decimal 3 places right. 1 200 which is 1200
4 * 10^-1 can be handled 2 ways 10 to the minus 1 in the denominator becomes 10^1 in the numerator. Notice the sign change on the 10 when you shift if :it becomes plus! That's why you did it.

1200 * 10^1 
12000

Now you are still left with 4 in the denominator.
12000/4 = 3000. 

The first method always works. The second one gives you a better understanding of how powers work. There are other ways of doing this, but these are the two best, I think.
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Fiona’s Number:
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Answer:

He should dial 289-743-1560

Step-by-step explanation:

The first three digits:  "My first three digits are the square of an integer less than twenty"

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Step 2:  "The first three digits are in ascending order" and no digits can repeat, so we eliminate the answers above that don't satisfy both of these condintions.  This leaves just 3 choices:

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*We will come back to this once we have more information.

The last 2 numbers: "the last two digits are multiples of sixty".  

The only 2 digit number that is a multiple of 60 is 60, so 6 and 0 are the last 2 digits.  This rules out two answers from Step 1 since no digits can repeat.  Only 289 works since 169 and 256 each have a 6 in them.  So now we know the first 3, and last 2 numbers!

                                     2 8 9 _ _ _ _ _ 6 0

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We want to find a 4 four digit number that has 60 as the last 2 digits.  Notice a pattern when you multiply 60 by certain digits...

60 x 1 = 60

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...

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60 x 21 = 1260     (this is the first 4 digit result, but it doesn't work because

                              there is a '2' in it, and 2 has already been used as the

                               first digit of the number)

60 x 26 = 1560     (this number could work, so lets try it and see if we can

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Now our number is

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If we assume that 1, 5, 6 and 0 are the last four digits, we know that 2, 8 and 9 are the first three digits, this leaves 3, 4 and 7 as the three remaining digits.  

3 + 4 + 7 = 14     so that condition is satisfied.   We just need to write then in descending order, so our final number is

289-743-1560

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