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3 years ago

List two tips for guessing on multiple-choice questions

SAT

2 answers:

timofeeve [1]3 years ago

5 0

If you don't know pick c and analyze the question

Zielflug [23.3K]3 years ago

5 0

Two tips for guessing on multiple choice questions are
Process of elimination( getting rid of the question that you know for sure aren’t the answer or make the least sense)
And
Pick the one that makes the most sense or relates to the topic most.

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Which are national us holidays? check all that apply.

Lisa [10]

There are different types of National holidays. The options that are National US holidays are New Year’s Day and Veterans Day

There are lots of national holidays in America. The United States is known to have has established using law, 12 permanent federal holidays.

They are; New Year's Day, Martin Luther King Jr.'s Birthday, Inauguration Day, George Washington's Birthday, Memorial Day, and Veterans Day, etc.

See full question below

Which are national us holidays? check all that apply.

A.) New Year’s Day

B.) Valentine’s Day

C.) Veterans Day

D.) Arbor Day

E.) Mothers Day

Learn more about National holidays from

brainly.com/question/25220143

4 0

2 years ago

B(n)=2^n A binary code word of length n is a string of 0's and 1's with n digits. For example, 1001 is a binary code word of len

Citrus2011 [14]

Answer:

The additional words is $2^n$

Explanation:

Given

$B(n) = 2^n$

Required

Determine the additional words; i.e. $B(n + 1) - B(n)$

From the given parameters, we have that;

B is a function of n

Such that;

$B(n) = 2^n$

To calculate $B(n+1)$ , we simply substitute n + 1 for n

$B(n) = 2^n$

$B(n + 1) = 2^{n + 1}$

Applying laws of indices

$B(n + 1) = 2^{n} * 2^1$

$B(n + 1) = 2^{n} * 2$

$B(n + 1) = 2(2^{n})$

Calculating Additional Binary Code;

$B(n + 1) - B(n)$

Substitute values for B(n + 1) and B(n)

$B(n + 1) - B(n) = 2(2^n) - 2^n$

Express $2^n$ as $2^ n * 1$

$B(n + 1) - B(n) = 2(2^n) - 2^n * 1$

Express 1 as $2^0$

$B(n + 1) - B(n) = 2(2^n) - 2^n * 2^0$

Factorize

$B(n + 1) - B(n) = 2^n(2 - 2^0)$

$B(n + 1) - B(n) = 2^n(2 - 1)$

$B(n + 1) - B(n) = 2^n(1)$

$B(n + 1) - B(n) = 2^n$

Hence, the additional words is $2^n$

8 0

3 years ago

For each blood group, indicate the antigens present on the RBCs and the antibodies present in the blood plasma.

VMariaS [17]

<h3>What is AB0 System?</h3>

The AB0 System represents an important blood group in determining compatibility between blood types.

The discovery of the AB0 system took place in 1901 and is due to the physician Karl Landsteiner (1868 - 1943). He and his team noticed that when some types of blood were mixed together, the red blood cells agglutinate, which is called blood incompatibility.

Thus, it was verified that there were some blood types, which were called A, B, AB and 0. Hence, the ABO system emerged.

The determination of blood types is a genetic condition, constituting a case of multiple alleles, determined by three alleles: IA, IB, i.

With that being said, in blood type A there are A antigens and antibodies for B antigens. In type B, is the opposite there are B antigens and antibodies for A antigens. In type 0, there are no antigens and there are antibodies for both antigens A and B. In type AB, There are both A and B antigens and there are no antibodies.

See more about genetics at: brainly.com/question/12985618

#SPJ1

3 0

2 years ago

How did the international community respond to South Africa’s policies in the 1980s? by refusing to buy South African goods by s

stepladder [879]

Answer:

A) By refusing to buy South African Goods

Explanation:

4 0

2 years ago

Por que os habitantes da cidade de Lobato usavam o petróleo para acender lamparinas?

spin [16.1K]

Yes they did use oil lamps

3 0

3 years ago