Answer:.
18 units^2.
Step-by-step explanation:
First find the length of 2 adjacent sides:
One length ( between the first 2 given points) = √ [ (4-1)^2 + (3-3)^2]
= 3.
The length of the adjacent side = √ [ (1-1)^2 + (3-9)^2 ]
= 6.
So the required area = 3 * 6
= 18.
X + Y = 50
X = Y + 6
X = 28
Y = 22
28 + 22 = 50
28 - 22 = 6 (28= 22 + 6)
There are 28 students in the larger class.
Hope this helps :)
I think the answer is -5.
Yes put that as an answer