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laila [671]
3 years ago
13

One quarter of Steve's baseball cards are from his dad's collection. Another 0.2 are from his uncle , and 0.5 are from his broth

er. The rest are from Steve's cousin. Thirty of the cards from his cousin are National League players; the other half are American League. How many cards are in his collection?
Mathematics
1 answer:
irina [24]3 years ago
4 0
.25+ .2 +.5= .95 so cousins cards make up 5% so 30 cards is half of that so that make 30 cards 2.5%. So 2.5 x 40 = 100% and 30 x 40=1200..... So Steve has 1200 baseball cards...... Hopefully I'm right... it just feels like it too much cards...;)
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To celebrate there 125 anniversary, a company in Germany produced 125 very expensive teddy bears. The bears,known as the "125 ka
liq [111]

Answer:

The cost of one bear is <u>$47,000</u>.

Step-by-step explanation:

The question is incomplete and the data is missing so the complete question with data is below with attached files:

To celebrate there 125 anniversary, a company in Germany produced 125 very expensive teddy bears. The bears,known as the "125 karat teddy bears", are made mohair,silk and gold thread and have diamond and sapphire eyes.

The chart shows the approximate cost of " 125 teddy bears". Based on the pattern, how much does one bear cost?

Now, to get the cost of one bear.

So, we solve it by using unitary method:

If 4 bears cost = $188,000.

Then 1 bear cost = 188000\div 4=47000

Thus, cost of one bear is $47,000.

Now, we check it by using another pattern of the data:

If 7 bears cost = $329,000.

Then 1 bear cost = 329000\div 7=47000.

Hence, the cost of one bear is $47,000.

Therefore, the cost of one bear is $47,000.

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adoni [48]

Answer:

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Step-by-step explanation:

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What is 5/6 plus 2 1/8. Thank you
Alecsey [184]
2 47/56
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3 0
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There are currently 17 frogs in a (large) pond. The frog population grows exponentially, tripling every 6 days. How long will it
Tema [17]

Answer:

t=11,11 days

Step-by-step explanation:

F=frogs poblation, t=time, be the variables dF/dt = KF, dF/F=Kdt, integrating \int\limits^ {} \, dF/F =K\int\limits^ {} \, dt⇒ LnF=Kt+c,F=ce^{Kt}; Knowing t=0, F=17 and t=6 F=51 (tripling every 6 days (17*3)), F=ce^{K0} = F=c=17; F=17e^{6K} =51⇒e^{6K} =51/17; K6=ln\frac{51}{17} ; K=ln\frac{51}{17}/6=0.183, so F=17e^{0,183t}, now if F=130, t=? we have:

130=17e^{0.183t} =e^{0.183t} =130/17; 0.183t=ln(130/17); t=ln(130/17)/0.183 = 11,11

8 0
3 years ago
PLEASE HELP. no links.
kobusy [5.1K]

Answer:

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Step-by-step explanation:

3 0
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