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Vilka [71]
3 years ago
6

Simplify the following expression as a monomial X^2y÷yx^2

Mathematics
1 answer:
Novay_Z [31]3 years ago
8 0

\bf ~\hspace{7em}\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
~\hspace{4.5em}
a^n\implies \cfrac{1}{a^{-n}}
~\hspace{4.5em}
\cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
x^2\div yx^2\implies \cfrac{x^2}{yx^2}\implies \cfrac{x^2\cdot x^{-2}}{y}\implies \cfrac{x^{2-2}}{y}\implies \cfrac{x^0}{y}\implies \cfrac{1}{y}

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Determine the end behavior of each rational function below. Graph each function on the graphing calculator, and
melomori [17]

Answer:

a) End behavior: As → ∞, () → . As → −∞, () → .

Looking at the ends of the graph, as goes to ∞ or −∞, gets

closer to .

b) End behavior: As → ∞, () → . As → −∞, () → .

Looking at the ends of the graph, as x goes to ∞ or −∞, gets

closer to .

c) End behavior: As → ∞, () → ∞, and as → −∞, () → −∞.

Looking at the ends of the graph, as goes to ∞, continues to increase

toward ∞, and as x goes to −∞, continues to decrease toward −∞.

Obs:. Graphics are attached

5 0
3 years ago
Bilal's favorite colors are red and green.
Arte-miy333 [17]

Answer:

P(A∪B) = 1/3

Step-by-step explanation:

Red  Garments = 1 red shirt + 1 red hat  + 1 red pairs of pants

Total Red Garments = 3

Green Garments =  1 green shirt + 1 green scarf + 1 green pairs of pants

Total Green Garments = 3

The total number of garments =  Total Red Garments + Total Green Garments:

3 + 3 = 6

Let A be the event that he selects a green garment

P(A) = Number of required outcomes/Total number of possible outcomes

P(A) =  3/6

Let B be the  event that he chooses a scarf

P(B) = 1/6

The objective here is to determine P(A or B) = P(A∪B)

Using the  probability set notation theory:

P(A∪B) = P(A) + P(B) - P(A∩B)

P(A∩B) = Probability that a green pair of pant is chosen = P(A) - P(B)

= 3/6-1/6

= 2/6

P(A∪B) = 1/2 + 1/6 - 2/6

P(A∪B) = 2/6

P(A∪B) = 1/3

8 0
3 years ago
Read 2 more answers
How do I do this plzzzz help​
LenaWriter [7]

Answer:

usually u add up or subtract everything and u get ur x y z answer i might be wrong

Step-by-step explanation:

8 0
3 years ago
If AJKL = ARST, which congruences are true by CPCTC? Check all that apply.
evablogger [386]

Based on the CPCTC theorem, the congruences that are true about the given triangles are:

B. ∠K ≅ ∠S

C. KL ≅ ST

D. JK ≅ RS

<h3>What is the CPCTC Theorem?</h3>

According to the CPCTC theorem states that if two triangles are congruent to each other, then, all their corresponding parts will be congruent to each other.

Given that triangles JKL and RST are congruent to each other, therefore:

∠J ≅ ∠R

∠K ≅ ∠S

∠L ≅ ∠T

JK ≅ RS

KL ≅ ST

JL ≅ RT

Therefore, the congruences that would be true by CPCTC are:

B. ∠K ≅ ∠S

C. KL ≅ ST

D. JK ≅ RS

Learn more about the CPCTC theorem on:

brainly.com/question/14706064

#SPJ1

5 0
2 years ago
What is the midpoint of the segment shown below?
a_sh-v [17]
B because it is the midpoint for segment shown above
5 0
3 years ago
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