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Andru [333]
3 years ago
13

5(2k - 3 )-3(k+4)/ 3k+2; k= -2

Mathematics
2 answers:
svetoff [14.1K]3 years ago
3 0

Answer:

First, we substitute k=-2 in the given expression and we calculate the numerical value.

\frac{5(2k-3)-3(k+4}{3k+2} =\frac{512(-2)-3](-2+4}{3(-2)+2}

=\frac{5(-4-3)-3(2)}{-6+2}

=\frac{5(-7)-6}{-4}

=\frac{-41}{-4}

=\frac{41}{4}

<u>OAmalOHopeO</u>

hoa [83]3 years ago
3 0

Answer:

-33

Step-by-step explanation:

5(2k - 3 )-3(k+4)/ 3k+2

5(2*(-2)-3)-3((-2)+4)/3*(-2)+2

5(-4-3)-3(2)/(-6)+2

5(-7)-6/(-6)+2

-35+1+2

-33

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7 0
3 years ago
Need help with this please! its due in a couple mins
user100 [1]
The first one is incorrect. The actual solution of the problem is 5/2. I’m sorry i’m in a rush right now. But that’s all I can answer right now.
7 0
3 years ago
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kaheart [24]

Answer:

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Step-by-step explanation:

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calculator for checking the answer:
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3 years ago
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Answer:

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Hope this helped!

6 0
3 years ago
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