Question

5(2k - 3 )-3(k+4)/ 3k+2; k= -2

Answer 1

Answer:

First, we substitute k=-2 in the given expression and we calculate the numerical value.

$\frac{5(2k-3)-3(k+4}{3k+2} =\frac{512(-2)-3](-2+4}{3(-2)+2}$

$=\frac{5(-4-3)-3(2)}{-6+2}$

$=\frac{5(-7)-6}{-4}$

$=\frac{-41}{-4}$

$=\frac{41}{4}$

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Answer 2

Answer:

-33

Step-by-step explanation:

5(2k - 3 )-3(k+4)/ 3k+2

5(2*(-2)-3)-3((-2)+4)/3*(-2)+2

5(-4-3)-3(2)/(-6)+2

5(-7)-6/(-6)+2

-35+1+2

-33