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andrew11 [14]
3 years ago
8

The length of a rectangle is four times its width. If the perimeter of the rectangle is 50 m, find its area

Mathematics
2 answers:
Sladkaya [172]3 years ago
6 0
Probably 100 m sqaure
Marianna [84]3 years ago
5 0
I believe it’s 100 m squared
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Which function is a quadratic function? c(x) = 6x + 3x3 d(x) = x – 8x4 p(x) = –5x – x2 k(x) = 2x2 + 9x4
Citrus2011 [14]
Easy
quadratic means 2nd degree

means highest power of exponent is 2
so like x^2

first one
we have 3x^3, that is 3rd degree,nope

2nd one
we have 8x^4, nope, that is 4th degree

3rd one
we have -x^2, yep

4th one, we have 9x^4, that is 4th degree

answer is 3rd one or p(x)=-5x-x^2
7 0
4 years ago
Read 2 more answers
What is x? -10 - x = -4
Musya8 [376]

Answer:

x = -6

Step-by-step explanation:

-10-x=-4 Add 10 to both sides...

-x=6 Divide both sides by -1...

x=-6

5 0
3 years ago
Sketch the graph of the function f(x) = -(x-4)^3 by indicating how a more basic function has been shifted, reflected, stretched,
irina [24]

Step-by-step explanation:

In the attached images we can see the rigid transformation of the function f(x) =x^{3}

1. The basic graph f(x) =x^{3}

2. The reflected graph f(x) = -x^{3}

3. The displaced graph f(x) = -(x-4)^{3}

Reflection: In the expression f(x) = -(x-4)^{3} , the sign - before the parenthesis indicates that the function is reflected in the x axis, for this case the function is even, this means that -f(x) = f(-x) , then the reflection on the x axis is equal to the reflection on the y axis.

Displacement: We observe the term (x-4) of the function f(x) = -(x-4)^{3} and analyze the value -4, where, the sign - indicates displacement to the right and the value 4 indicates the amount that the graph shifted .

3 0
4 years ago
The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati
makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\

And the second one would be

y = 2-x \,\,\,\,\,,  1 \leq x \leq 2.

If you rotate the first region around the "y" axis you get that

{\displaystyle A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51 }

And if you rotate the second region around the "y" axis you get that

{\displaystyle A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188 }

And the sum would be  2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first  region around the x axis you get that

{\displaystyle A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708 }

And if you rotate the second region around the x axis you get that

{\displaystyle A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472 }

And the sum would be 1.5708+1.0472 = 2.618

7 0
4 years ago
What's the value 2s in 2,200
inessss [21]
The first two is worth 2,000 and the second is worth 200. 
8 0
3 years ago
Read 2 more answers
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