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goldfiish [28.3K]
3 years ago
8

Explain how 4/10÷2 and 4/10×1/2 both equal 2/10.

Mathematics
1 answer:
iris [78.8K]3 years ago
5 0

Answer:

Step-by-step explanation:

when you are taking (4/10) and dividing it by 2.  you have a fraction over a fraction.  if you remember what you do to the top part of the equation you do to the bottom.  so we want to get rid of dividing by 2.  (multiple by the reciprocal)  the reciprocal of 2 is 1/2.  that will cancel out the bottom part of the equation but what you do to the bottom you have to do to the top.  so,  (4/10) * 1/2 is the same as (4/10) divided by 2. hope that makes sense.  it's much easier to write out then type math...

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Decimal form : 2.61728395
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4 years ago
cost $12 for adults and 5$ for children .on the first day of the fair 312 tickets were sold for a total of 2204$.How many adults
IrinaVladis [17]

The number of adult tickets and children tickets sold were 92 and 220 respectively

What differentiate adult tickets from children's

The adult tickets can be represented by a while children's ticket is c

The total number of tickets sold which is 312 means the sum of a and c

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Total value of adult tickets=a*12

total value of children tickets=c*5

12a+5c=2204

Solve for a in the first equation

a=312-c

substitute for a in the second equation

12a+5c=2204

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3744-12c+5c=2203

3744-2203=12c-5c

1541=7c

c=1541/7

c=220

a=312-220

a=92

Find out more about ticket pricing on: brainly.com/question/13711180

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3 0
2 years ago
You are going to use an incline plane to lift a heavy object to the top of a shelving unit with a height of 5 ft. The base of th
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Answer:

16.8 ft

Step-by-step explanation:

use pythagorean formula

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A package of ground beef costs $6.98. The price per pound is $1.86. How many pounds of ground beef are in the package? Round to
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6. A tank contains 100-gallon of pure water. At time t = 0, a solution containing 2 lb of salt per gallon flows into the tank at
SOVA2 [1]

Answer:

The answer is below

Step-by-step explanation:

Let Q represent the amount of salt in the tank at time t.

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Integrating:\\\\A(100-t)^{-4}=-2(100-t)^{-3}+c\\\\A=-2(100-t)+\frac{c}{(100-t)^{-4}} \\\\at, t=0,A=0\\\\0=-2(100-0)+\frac{c}{(100-0)^{-4}}\\\\c=0.02\\\\A=-2(100-t)+\frac{0.02}{(100-t)^{-4}}

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3 years ago
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