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miskamm [114]
3 years ago
12

Help me solve -2+5n=4n+2

Mathematics
1 answer:
iris [78.8K]3 years ago
7 0
Sorry for the messy handwriting
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Factor and add steps please<br><br> 81u^6+192
attashe74 [19]
ANSWER : (9u - 8)2



STEPS:

Step-1 : Multiply the coefficient of the first term by the constant 81 • 64 = 5184

Step-2 : Find two factors of 5184 whose sum equals the coefficient of the middle term, which is -144 .

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -72 and -72
81u2 - 72u - 72u - 64

Step-4 : Add up the first 2 terms, pulling out like factors :
9u • (9u-8)

Step-5 : Add up the four terms of step 4 :
(9u-8) • (9u-8)
Which is the desired factorization



5 0
1 year ago
11. Identify the properties below.<br> a. 5 + 6 = 6 + 5<br> b. 7 + (3 + 9) = (7 + 9) + 3
jenyasd209 [6]
A is commutative property
B is associative property
Explanation:
5 0
3 years ago
Help ASAP CLICK THE PIC
Jet001 [13]

Answer:

10

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Does the set of numbers form a Pythagorean triple? Explain.
Natali [406]

Answer:

NO

Step-by-step explanation:

Either 3, 5 and 6 satisfy the Pythagorean Theorem or they do not.  Here we start with a^2 + b^2 = c^2 and substitute 6 for c (because 6 is the largest of the set):  Is 3^2 + 5^2 = 6^2?  9 + 25 = 36?  NO

7 0
2 years ago
Suppose that you are in charge of evaluating teacher performance at a large elementary school. One tool you have for this evalua
Strike441 [17]

Answer:

a) Standard error = 2

b) Range = (76.08, 83.92)

c) P=0.69

d) Smaller

e) Greater

Step-by-step explanation:

a) When we have a sample taken out of the population, the standard error of the mean is calculated as:

\sigma_m=\dfrac{\sigma}{\sqrt{n}}=\dfrac{10}{\sqrt{25}}=\dfrac{10}{5}=2

where n is te sample size (n=25) and σ is the population standard deviation (σ=10).

Then, the standard error of the classroom average score is 2.

b) The calculations for this range are the same that for the confidence interval, with the difference that we know the population mean.

The population standard deviation is know and is σ=10.

The population mean is M=80.

The sample size is N=25.

The standard error of the mean is σM=2.

The z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=1.96 \cdot 2=3.92

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 80-3.92=76.08\\\\UL=M+t \cdot s_M = 80+3.92=83.92

The range that we expect the average classroom test score to fall 95% of the time is (76.08, 83.92).

c) We can calculate this by calculating the z-score of X=79.

z=\dfrac{X-\mu}{\sigma}=\dfrac{79-80}{2}=\dfrac{-1}{2}=-0.5

Then, the probability of getting a average score of 79 or higher is:

P(X>79)=P(z>-0.5)=0.69146

The approximate probability that a classroom will have an average test score of 79 or higher is 0.69.

d) If the sample is smaller, the standard error is bigger (as the square root of the sample size is in the denominator), so the spread of the probability distribution is more. This results then in a smaller probability for any range.

e) If the population standard deviation is smaller, the standard error for the sample (the classroom) become smaller too. This means that the values are more concentrated around the mean (less spread). This results in a higher probability for every range that include the mean.

6 0
3 years ago
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