So the original area is 300*150 (or 45000 ft^2), but now the new area is (300+3y)(150+3y).
The polynomial in standard form would be 45000+900y+450y+9y^2=45000+1350y+9y^2
But the proper way to write it is 9y^2+1350y+45000
When y=4, we get 9(4^2)+1350(4)+45000=9(16)+54000+45000=144+99000=99144
So the new area would be 99144 ft^2
Hope this helped!
A
using the Cosine rule in ΔSTU
let t = SU, s = TU and u = ST, then
t² = u² + s² - (2us cos T )
substitute the appropriate values into the formula
t² = 5² + 9² - (2 × 5 × 9 × cos68° )
= 25 + 81 - 90cos68°
= 106 - 33.71 = 72.29
⇒ t = 
≈ 8.5 in → A
We'll use PEMDAS which stands for
P = parenthesis
E = exponents
M = multiplication
D = division
A = addition
S = subtraction
It tells us the order in how to evaluate math expressions. We start with parenthesis, then move to exponents, etc until we get to subtraction as the last step.
We have parenthesis so we focus on whats inside it. We evaluate 2^0 to get 1. Any nonzero number to the exponent 0 is always 1. In other words, x^0 = 1 where x is nonzero.
So 3(2^0) turns into 3(1) or 3*1
Then we multiply that to get 3*1 = 3
So overall, 3(2^0) = 3
