The question is asking what v_final is, given that v_initial is at 300 feet. and v_initial is at 0 feet.
We know there will be a constant downward acceleration of 32.15 ft/s^2.
Use the following equation:
v_final^2 = v_initial^2 + 2ah
v_final^2 = (160 ft/s)^2 + 2(-32.15 ft/s^2)(300 ft) = 6310 ft^2/s^2
v_final = (6310 ft^2/s^2)^1/2 = 79.4 ft/s.
I can’t do this for you, you have to drag the segments into the boxes. The fifth over is A. then you do the first line segment. Then the third. for D you do the fifth over
64=-4+4x
64+4=4x
68=4x
68/4=x
17=x
(4,4) are the coordinates of C prime
the Answer is 4 do order of operations