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3 years ago

What is the angle in a triangle that is part of a linear pair?

2 answers:

5 0

If you understand what is linear pair, you can see the same in triangle also. A linear pair is a pair of adjacent, supplementary angles. Adjacentmeans next to each other, and supplementary means that the measures of the two angles add up to equal 180 degrees.

Mamont248 [21]3 years ago

5 0

The linear pair should equal 180, added together.

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Solve for Y:<br> 2/3 (y+57 )= 178

sattari [20]

Y= 210 you have to distribute 2/3 to y then to 57 and your equation would be 2/3y + 38= 178 then you take 38 and subtract 178 - 38 and you get 140 then you divide 140/ (2/3) and you will get 210 as your answer.(:

8 0

3 years ago

Determine the domain of the following graph

Lunna [17]

Answer:

-3 ≥ x ≥ 9

Step-by-step explanation:

The domain are the x-values of every point in your graph. Since it a continuous domain, it'll be represented with ≥. Your two extremities are -3 and 9. Therefore, your domain is -3 ≥ x ≥ 9.

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3 years ago

I paid $8.50 each for movie tickets and i spend a total of $144.50. If n, represents how many tickets i bought, write and equati

damaskus [11]

Answer:
$144.50/8.50 = n

Explanation:
The word each indicates this equation will use division. We know the total is 144.50, so that will be the number being divided. 8.50 is the number 144.50 is divided by. The quotient will be represented by the variable, n.

8 0

3 years ago

Read 2 more answers

A cylinder has a base radius of 6ft and a height of 18ft. What is its volume in cubic ft, round to the nearest tenth?

Nookie1986 [14]

Answer:2034.7

Step-by-step explanation:

The equation is pi •r^2•h

R=6

H=18

3 0

3 years ago

The compressive strength of concrete is normally distributed with mu = 2500 psi and sigma = 50 psi. A random sample of n = 8 spe

Nata [24]

Answer:

$X \sim N(2500,50)$

Where $\mu=2500$ and $\sigma=50$

We select a sample size of n =8. Since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$SE = \frac{50}{\sqrt{8}}= 17.678 psi$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

Let X the random variable that represent the compressive strength of concrete of a population, and for this case we know the distribution for X is given by:

$X \sim N(2500,50)$

Where $\mu=2500$ and $\sigma=50$

We select a sample size of n =8. Since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$SE = \frac{50}{\sqrt{8}}= 17.678 psi$

7 0

3 years ago