Using Laplace transform we have:L(x')+7L(x) = 5L(cos(2t))sL(x)-x(0) + 7L(x) = 5s/(s^2+4)(s+7)L(x)- 4 = 5s/(s^2+4)(s+7)L(x) = (5s - 4s^2 -16)/(s^2+4)
=> L(x) = -(4s^2 - 5s +16)/(s^2+4)(s+7)
now the boring part, using partial fractions we separate 1/(s^2+4)(s+7) that is:(7-s)/[53(s^2+4)] + 1/53(s+7). So:
L(x)= (1/53)[(-28s^2+4s^3-4s^2+35s-5s^2+5s)/(s^2+4) + (-4s^2+5s-16)/(s+7)]L(x)= (1/53)[(4s^3 -37s^2 +40s)/(s^2+4) + (-4s^2+5s-16)/(s+7)]
denoting T:= L^(-1)and x= (4/53) T(s^3/(s^2+4)) - (37/53)T(s^2/(s^2+4)) +(40/53) T(s^2+4)-(4/53) T(s^2/s+7) +(5/53)T(s/s+7) - (16/53) T(1/s+7)
Answer:
(x-y)(x-y-3)
Step-by-step explanation:
(x-y)² - 3(x-y)
take (x-y) common,
(x-y)(x-y-3)
Answer:
1 cm
Step-by-step explanation:
To solve this problem we can use the Pythagorean theorem. In fact the diagonal of a rectangle is an hypotenuse of a right triangle, while the length is a leg. The width is the other leg
width = √2^2 - (√3)^2 = √4 - 3 = √1 = 1 cm
Answer:
a = 629
Step-by-step explanation:
a = w * L
w = 17
L = 2w + 3
a = (17) * (2w + 3)
a = (17) * (2(17) + 3)
a = 17 * (34 + 3)
a = 17 * (37)
a = 629
Answer:
0.63
Step-by-step explanation:
To get the relative frequency of students with red hair, we need to find the relative frequency of students with red hair from the students with gray eyes.
Since we already know that the total number of students with gray eyes is 35 and the number of red hair students with gray eye is 22
The formula we will use to calculate the relative frequency will be
The relative frequency of students with red hair = Total students of red hair with gray eyes divide by total number of gray eye students
22 ÷ 35 = 0.628 ≅ 0.63
