Let w won games, t tied games, s lose games
s=4w
t=w-5
s+t+w=43
4w+(w-5)+w=43
6w=48
w=7
s=4*7=21 games lost
Answer:
<h2>2x^3+3x^2</h2>
Step-by-step explanation:
<h3>x^2(2x+3)</h3><h3 /><h3>=(x^2)(2x+3)</h3><h3 /><h3>=(x^2)(2x)+(x^2)(3)</h3><h3 /><h3>=2x^3+3x^2</h3>
The answer is c because the number of tickets (t) times the number of adults is the total cost
Firstly, you've got to expand the brackets, this becomes;
8a-4= -10a+ 50
You've then got to eliminate the -10a and you do this by adding 10a to both sides,
This then becomes 18a-4=50
You've then got to add 4, to eliminate this, which then becomes 18a=54
You've then got to divide both sides by 18, and this becomes 3.
Therefor, a=3
Hope this helps :)
