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tigry1 [53]
3 years ago
6

Make 2X2+6X +4 equal 24 I need help

Mathematics
1 answer:
Reika [66]3 years ago
4 0

Answer:

X=2 or -5

Step-by-step explanation:

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The smiths have saved $25,000 toward the purchase of a new car. If the sales tax is 5%, the purchase price of smiths new car bef
lukranit [14]

Answer:

26,250

Step-by-step explanation:

25,000 + 5% = 26,250

:) please mark Brainliest

8 0
4 years ago
Two drunks start out together at the origin, each having equal probability of making a step to the left or right along the x axi
pashok25 [27]
They'll meet wen they are sober lol
7 0
3 years ago
Solve in quadratic formula (show work)<br> <img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B5x%2B1%3D0" id="TexFormula1" titl
olga2289 [7]

Answer:

x= −5±√17/4

Step-by-step explanation:

6 0
3 years ago
A recent survey suggests that 85% of college students have a job, 54% live on campus, and 42% have a job and live on campus. Wha
OLga [1]

\frac{97}{100} probability that a randomly chosen college student either has a job or lives on campus.

What is probability?

  • Probability is an area of mathematics that deals with numerical descriptions of how probable an event is to occur or how likely a statement is to be true.
  • The probability of an event is a number between 0 and 1, where 0 denotes the event's impossibility and 1 represents certainty.

To find the probability that a randomly chosen college student either has a job or lives on campus:

Given: 85% of college students have a job, 54% live on campus, and 42% have a job and live on campus.

So, out of 100 students, 42 students either has a job or live on campus.

43 college students have a job and 12  live on campus.

So, 43 + 42 + 12 = 85 + 54 - 42

85 + 12 = 139 - 42

97 = 97

Therefore, \frac{97}{100} probability that a randomly chosen college student either has a job or lives on campus.

Know more about probability here:

brainly.com/question/24756209

#SPJ4

3 0
2 years ago
Solve the quadratic equation: 3x2 + x - 5 = 0
Yuri [45]

Hey there!

3x^2 + x -5 = 0

This equation is in standard form, which is ax^2+bx+c=0.

We are going to solve this with the quadratic equation, so we need to find the values for a, b, and c in the given equation. We can just look at it and identify the variables.

a = 3, b = 1, c = -5

Let's plug these values into the quadratic equation:

x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}

x=\frac{-1\pm\sqrt{1^2-4(3)(-5)} }{2(3)}

Multiply 4(3)(-5) together and multiply 2(3). Square 1.

x=\frac{-1\pm\sqrt{1+60} }{6}

Add 1 and 60.

x=\frac{-1\pm\sqrt{61} }{6}

This is our answer in exact form. If you need this as an approximate value, let me know and I will do that for you.

Hope this helps!

8 0
3 years ago
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