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3 years ago

Can someone please show me how 19169000*e^(0.15)= 222712201 When e= 2.7182818284?

Mathematics

1 answer:

Ierofanga [76]3 years ago

8 0

Answer:

It doesn't. x = 22 271 201

Step-by-step explanation:

You are going to need a calculator no matter how you do it.

$x =19 169 000 \times e^{0.15}$

(a) The direct method

$x = 19 169 000\times 2.718 281 828^{0.15} = 19 169 000 \times 1.161 834 243 = 22 271 201$

(b) The indirect method

$\ln \left (19 169 000\times 2.718 281 828^{0.15} \right ) = \ln(19 169 000) + 0.15 = 16.768 805 + 0.15 = 16.918 804\\\\e^{16.918 804} = 22 271 201$

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Answer:

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Step-by-step explanation:

This system of equations can be used to find the price of the adult and child tickets.

We have two equations (one for each day) and two unknowns (adult ticket price and child ticket price).

Let a: adult ticket price and c: child ticket price,

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and for the second day we have that 2 adult tickets and 2 child tickets adds $52:

$3a+2c=52$

If we write this as a system of equations, we have:

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storchak [24]

The result of the square root of the equation A = 121 ft² is √A = 11 ft

<h3>What are square roots?</h3>

Square roots are numbers multiplied by itself to give another number

<h3>How to determine the square root?</h3>

The equation is given as:

A = 121 ft²

Take the square root of both sides

√A = √121 ft²

Evaluate the square root

√A = 11 ft

Hence, the square root of the equation A = 121 ft² is √A = 11 ft

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Directions: State whether or not (3, -2) is a solution to the following systems.

andrew11 [14]

(3, -2) is a solution to the system of equations x - 2y = 7 and 2x + 3y = 0, (3, -2) is not a solution to the system of equations -x - y = -5 and 3x - 4y = 17 and (3, -2) is not a solution to the system of equations x + y = 1 and x - y = 6

<h3>How to determine the whether or not (3, -2) is a solution to the following systems?</h3>

The systems of equations are given as:

1. x - 2y = 7 and 2x + 3y = 0

2. -x - y = -5 and 3x - 4y = 17

3. x + y = 1 and x - y = 6

Next, we substitute (3, -2) for (x, y) in the system of equations.

So, we have:

3 - 2 * -2 = 7 and 2 * 3 + 3 * -2 = 0

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Hence, (3, -2) is a solution to the system of equations x - 2y = 7 and 2x + 3y = 0

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Evaluate

- 1 = - 5 and 1 7 = 1 7

The above equation is false

Hence, (3, -2) is not a solution to the system of equations -x - y = -5 and 3x - 4y = 17

3 - 2 = 1 and 3 + 2 = 6

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1 = 1 and 5 = 6

The above equation is false

Hence, (3, -2) is not a solution to the system of equations x + y = 1 and x - y = 6

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