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Furkat [3]
3 years ago
6

An assembly line with 10 tasks needs be designed. The total time for all tasks is 16 minutes. If you need to produce 30 units/ho

ur, how many minimum work stations will be needed
Mathematics
1 answer:
Sindrei [870]3 years ago
5 0

Answer: 8 minimum work stations is what would be needed.

Step-by-step explanation:

The cycle time is computed as the operating time daily divided by the scheduled output.

It is important to note that the daily capacity of the operation layout is the operating time divided by the cycle time.

Therefore,

If you need to produce 30units/hour.

The average cycle time is as follow:

The average cycle time is the average time between the completions of units.

60/30= 2 average cycle time

=16/2

=8

8 work stations is the minimum number that would be needed.

It is important to know that in an assembly line balancing, the minimum number of work station is the ratio of the sum of all tasks time to the cycle time.

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7^2 + 5^2 = 49 + 25 = 74

hypotenuse = square root of 74

Answer is B

Step-by-step explanation:

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Are these rates equivalent, 96 words typed for 3 minutes; 160 words typed for 5 minutes
monitta
<h2>Greetings</h2>

Answer:

Yes, they are.

Step-by-step explanation:

<h3>1st rate)</h3>

Lets simplify both rates to the rate typer per minute.

(m is minutes)

3m = 96

Divide both sides by 3:

\frac{3m}{3} = \frac{96}{3}

m = 32

So the rate is 32 words per minute.

<h3>2nd rate</h3>

5m = 160

Divide both sides by 5:

\frac{5m}{5} = \frac{160}{5}

m = 32

<h3>So because the rates per minute are the same, they are equivalent.</h3>
<h2>Hope this helps!</h2>
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3 years ago
Cindy types 180 words in 2 minutes
Mamont248 [21]
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A cube made out of lead has a mass of 12 grams. A side of the cube has length 1 cm. What would be the mass of the cube whose sid
Ulleksa [173]

Answer:

<h3><em><u>The mass of a lead cube whose </u></em><em><u>side </u></em><em><u>have length 1.5 cm is 40.5 </u></em><em><u>grams</u></em></h3>

Step-by-step explanation:

<u>1. Let's review the information given to</u>

<u>1. Let's review the information given tous to answer the question correctly:</u>

<u>1. Let's review the information given tous to answer the question correctly:Mass of the cube made out of lead</u> = 12

= 12grams

Side of the cube <em>= 1 cm</em>

2. <em><u>What would be the mass of a lead</u></em>

<em><u>What would be the mass of a leadcube whose sides have length 1.5 cm?</u></em>

<em><u>What would be the mass of a leadcube whose sides have length 1.5 cm?For answering the question, let's</u></em>

<em><u>What would be the mass of a leadcube whose sides have length 1.5 cm?For answering the question, let'scalculate the volume of the cube and</u></em>

<em><u>What would be the mass of a leadcube whose sides have length 1.5 cm?For answering the question, let'scalculate the volume of the cube andthen its density, this way:</u></em>

<h3>Volume = Height* Width * Length</h3><h3>Volume=1*1*1</h3><h3>Volume =1 cm</h3>

Let's recall the formula of the density:

Density Mass/Volume, therefore:

Density of the lead <em><u>= 12/1= 12 gr/</u></em><em><u>cm</u></em>

<em><u>Now, let's calculate the volume of the</u></em>

<em><u>Now, let's calculate the volume of thesecond cube:</u></em>

<h3><em>Volume = Height Width Length</em></h3><h3><em>Volume = Height Width LengthVolume 1.5 * 1.5 1.5</em></h3><h3><em>Volume = Height Width LengthVolume 1.5 * 1.5 1.5Volume =3.375 cm3</em></h3>

<u>Finally, let's calculate the mass, using</u>

<u>Finally, let's calculate the mass, usingthe density of the lead we already</u>

<u>Finally, let's calculate the mass, usingthe density of the lead we alreadyknow:</u>

<h3>Density = Mass/Volume</h3><h3><em>12 Mass/3.375</em></h3><h3><em>12 Mass/3.375Mass 12 *3.375</em></h3><h3><em>12 Mass/3.375Mass 12 *3.375Mass = 40.5 gramss</em></h3>
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2 years ago
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