2 years ago

I need someone to figure out these two problems please

Mathematics

1 answer:

Korolek [52]2 years ago

6 0

Answer:

assuming all the cut off squares are exactly one half (because that wasn't specified) 1 is 33 and 2 is 19

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Read 2 more answers

What is sin 0 when sec 0 = 5? 0 |(1,0) sin e = 2[?] [] Rationalize the denominator if necessary.

Komok [63]

Answer:

$Sin ~0 =\frac{2\sqrt{5} }{5}$

Step-by-step explanation:

$sec0=\sqrt{5}$

$cos~0=\frac{1}{sec0} =\frac{1}{\sqrt{5} }$

$sin ~0=\sqrt{1-cos^2~0}$

$=\sqrt{1-1/5}=\sqrt{5-1/5}$

$Sin~0=\sqrt{4/5} =2/\sqrt{5}*\sqrt{5}/\sqrt{5}$

$Sin~0=2\sqrt{5}/2=2\sqrt{5}/5$

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hope it helps...

have a great day!!!

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3 years ago