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3 years ago

If s(x)=x-7 and t(x) =4x^2+3 which expression is equivalent to (t×s)(x)

Mathematics

1 answer:

marshall27 [118]3 years ago

8 0

Answer:

$\large\boxed{(t\times s)(x)=4x^3-28x^2+3x-21}$

Step-by-step explanation:

$s(x)=x-7\\t(x)=4x^2+3\\\\(t\times s)(x)=t(x)\times s(x)\\\\\text{Substitute:}\\\\(t\times s)(x)=(4x^2+3)(x-7)\\\\\text{use FOIL:}\ (a+b)(c+d)=ac+ad+bc+bd\\\\(t\times s)(x)=(4x^2)(x)+(4x^2)(-7)+(3)(x)+(3)(-7)\\\\=4x^3-28x^2+3x-21$

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Also, let 'A' be the event that the person wins at least one game of blackjack. Then, the outcomes of Event 'A' are

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Let
s-------> represent the number of sheep
g-------> represent the number of goats

we know that
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so
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therefore

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2 years ago

If s(x)=x-7 and t(x) =4x^2+3 which expression is equivalent to (t×s)(x)​

If s(x)=x-7 and t(x) =4x^2+3 which expression is equivalent to (t×s)(x)