Find tan θ for θ = 60° .
1 answer:
You might be interested in
Answer:
x = - 4 ± 2
Step-by-step explanation:
Given
f(x) = x² + 8x + 4
To find the zeros let f(x) = 0, that is
x² + 8x + 4 = 0 ( subtract 4 from both sides )
x² + 8x = - 4
To solve using the method of completing the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(4)x + 16 = - 4 + 16
(x + 4)² = 12 ( take the square root of both sides )
x + 4 = ± = ± 2
( subtract 4 from both sides )
x = - 4 ± 2
Thus the zeros are
x = - 4 - 2 and x = - 4 + 2
The magnitude of the vectors is 7.2
The magnitude of a vector is resolved by using a formula
<h3>Magnitude of a Vector</h3>This is the displacement between two vectors and can be calculated as
where x is the magnitude of displacement between y and z.
In this question, the vectors are
- -4
- -6
Let's find the magnitude of this vector
The magnitude of the vectors is 7.2
Learn more on magnitude of vectors here;
You would distribute each number. Then afterwards simplify what you have into standard form. Once you have it in standard form you use the quadratic formula. The end answers are 1 and 7
