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2 years ago

Help pleaseeeeeeeeeeeeeeeeeeeeeee

Mathematics

1 answer:

Dima020 [189]2 years ago

8 0

Answer:

B'C'D'

Step-by-step explanation:

The figure was just translated, without any deformation, these are similar figures... so their corresponding angles are the same.

Since it was just moved down by 4 units, none of the angles were changed, and none of the side lengths were changed.

Since vertex C' corresponds to vertex C, the angle B'C'D' corresponds to original angle BCD.

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Easy math please help

Vaselesa [24]

A and D
Explanation: I did this problem in khan academy

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2 years ago

0.3 km = ? mi. rounded to the nearest hundred

Sergio [31]

Answer:

0.19

Step-by-step explanation:

There are approximately .62 miles in a kilometer

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3 years ago

Read 2 more answers

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goldfiish [28.3K]

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2 years ago

It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp

Semmy [17]

Answer:

$\frac{1}{5}$

Step-by-step explanation:

Using the rules of exponents

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$ , $\frac{a^{m} }{a^{n} }$ = $a^{(m-n)}$ , $(a^m)^{n}$ = $a^{mn}$

Simplifying the product of the first 2 terms

$\frac{a^{p^2+pq} }{a^{pq+q^2} }$ × $\frac{a^{q^2+qr} }{a^{qr+r^2} }$

= $a^{p^2-q^2}$ × $a^{q^2-r^2}$

= $a^{p^2-r^2}$

Simplifying the third term

5( $(a^p+r)^{p-r}$

= 5 $a^{(p+r)(p-r)}$ = 5 $a^{(p^2-r^2)}$

Performing the division, that is

$\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} }$ ← cancel $a^{(p^2-r^2)}$ on numerator/ denominator leaves

= $\frac{1}{5}$

4 0

2 years ago

Hunter's time for the 100-meter freestyle event was 57.9 seconds. His time for the second half of the race was 4.7 seconds slowe

Ratling [72]

Answer:

Step-by-step explanation:

Time for first race 57.9seconds

x=time for first half of race

x-4.7=second half of race

Equations is

x + (x-4.7)=57.9

2x-4.7=57.9

2x=57.9+4.7

2x=62.6

x=31.3

Check answer

31.3 + (31.3-4.7)=57.9

31.3 +26.6=57.9

57.9=57.9

6 0

3 years ago