Answer:
Step-by-step explanation:
Given tq equation of the height reached by the rocket as y=-16x^2+235x+133
The velocity of the object at its maximum height is zero
v = dy/dx = 0(at max height)
v =-32x +235
0 =-32x+235
x = 235/32
x = 7.34
Hence the rocket will reach its maximum height after 7.34seconds
So all positive integers is the domain (the number you can use)
and the range (the numbers you get when you put the numbers in the domain in) is all positive integers more than 2
Franco:
3x+2y=19
Caryl:
2x+4y=24
now use elimination
-2(3x+2y=19)
1(2x+4y=24)
=
-6x-4y=-38
2x+4y=24
add them together
which equals -4x=-14
divide both sides by -4
-4x/-4=-14/-4
x=7/2
we found x, so we subsitute it into the the original equation
3x+2y=19
3(7/2)2y=19
2y+21/2=19
-21/2 -21/2
2y=17/2
divide by 2 on both sides
2y/2= 17/2/2
y=17/4
so x= 7/2 and y= 17/4
Answer:
Verified
Step-by-step explanation:
Use 
, 
and 
LHS=
=RHS
